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2 years ago

Grade 12mathematics(√98-√50)²

Mathematics

1 answer:

allsm [11]2 years ago

4 0

Answer:

Step-by-step explanation:

Two different approaches:

Method 1

Apply radical rule √(ab) = √a√b to simplify the radicals:

√98 = √(49 x 2) = √49√2 = 7√2

√50 = √(25 x 2) = √25√2 = 5√2

Therefore, (√98 - √50)² = (7√2 - 5√2)²

= (2√2)²

= 4 x 2

= 8

Method 2

Use the perfect square formula: (a - b)² = a² - 2ab + b²

where a = √98 and b = √50

So (√98 - √50)² = (√98)² - 2√98√50 + (√50)²

= 98 - 2√98√50 + 50

= 148 - 2√98√50

Apply radical rule √(ab) = √a√b to simplify radicals:

√98 = √(49 x 2) = √49√2 = 7√2

√50 = √(25 x 2) = √25√2 = 5√2

Therefore, 148 - 2√98√50 = 148 - (2 × 7√2 × 5√2)

= 148 - 140

= 8

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Second transformation (rotation counter clockwise (-y,x))

$\begin{gathered} P_1(-2,2)\rightarrow P^{\prime}_1(-2,-2)_{} \\ P_2(-2,4)\rightarrow P^{\prime}_2(-4,-2) \\ P_3(-5,2)\rightarrow P^{\prime}_3(-2,-5)_{} \\ P_4(-5,4)\rightarrow P^{\prime}_4(-4,-5)_{} \end{gathered}$

Third Transformation (reflection over y-axis (-x,y))

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Grade 12mathematics(√98-√50)² ​

Grade 12mathematics(√98-√50)²