Given
5(x + 27) ≥ 6(x + 26)
Find
The solution set of x
Solution
Eliminate parenthses.
... 5x + 135 ≥ 6x + 156
Subtract 5x+156
... -21 ≥ x
The solution set is all real numbers less than or equal to -21.
Answer:
E
Step-by-step explanation:
In the picture attached, the Truth Table for the operator “OR” is shown. With it we can compute the next table:
p q ∧ r p ∨ (q ∧ r)
T T T
T F T
F T T
F F F
We want that p would be false and p ∨ (q ∧ r) would be true, which corresponds to the third row of the previous table.
The only row from the table of the question that satisfies this criterion is row E.
Answer:
x=3 and y=2
Step-by-step explanation:
1.) 4x+3(5x-13)=18
expand into 4x+15x-39=18
18+39= 57
15x+4x= 19x
57/19= 3 so x=3
substitute 3 into y= 5x - 13
and you get 2 so y=2
Answer:
x= 1/4k + −11/4
Step-by-step explanation:
4x+11=k
Step 1: Add -11 to both sides.
4x+11+−11=k+−11
4x=k−11
Step 2: Divide both sides by 4.
4x/4 = k−11/4
x=1/4k + −11/4
Answer:
x=1/4k + −11/4
OR
If you are solving for K:
Let's solve for k.
4x+11=k
Step 1: Flip the equation.
k=4x+11
Answer:
k=4x+11
