36 is the answer. Hope this helped!
Answer: the term number is 38
Step-by-step explanation:
Let the number of the term be x
The value of the xth term = 488
In an arithmetic sequence, the terms differ by a common difference, d. This means that the difference between two consecutive terms, d is constant.
The formula for the nth term is
Tn = a + (n-1)d
Where
Tn = the nth term of the arithmetic sequence
a = the first term of the arithmetic sequence.
d = common difference.
From the information given,
a = 7
d = 13
We are looking for the xth term.
Tx = 488 = 7 + (x-1)13
488 = 7 + 13x - 13
Collecting like terms on the left hand side and right hand side of the equation,
13x = 488 -7 + 13
13x = 494
x = 38
The value of the 38th term is 488.
Answer: A) max at (14, 6) = 64, min at (0,0) = 0
<u>Step-by-step explanation:</u>
Graph the lines at look for the points of intersection.
Input those points into the Constraint function (2x + 6y) and look for the maximum value and minimum value.
Points of Intersection: (0, 0), (17, 0), (0, 10), (14, 6)
Point Constraint 2x + 6y
(0, 0): 2(0) + 6(0) = 0 Minimum
(17, 0): 2(17) + 6(0) = 34
(0, 10): 2(0) + 6(10) = 60
(14, 6): 2(14) + 6(6) = 64 Maximum
Answer:
The last one the one with (-6,00) and Range (5,00)
