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2 years ago

Use the definition of complementary angles to solve for x.

Mathematics

1 answer:

salantis [7]2 years ago

5 0

Answer:

x = 4 and x = 7

Step-by-step explanation:

→ Find the sum of both the angles

3x + x + 74 = 4x + 74

6x + x + 13 = 7x + 13

→ Equate both equations to 90

4x + 74 = 90

7x + 13 = 90

→ Minus 74 and 13

4x = 16

7x = 77

→ Divide by 4 and 7 respectively

x = 4 and x = 7

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An architect's model for a building is 1.4 m long and 0.8 m wide. The actual building is 240 m wide. What is the length of the b

mina [271]

Answer:

214.285714286 m

Step-by-step explanation:

240/1.4

240/1.4/0.8

7 0

3 years ago

Read 2 more answers

Mia found the area of a polygon The area is 32 square cm.

solniwko [45]

Answer:

Only the isosceles trapezoid has an area of 32 cm².

Step-by-step explanation:

Let's calculate the area of each polygon.

For the two triangles we have:

$A_{t} = \frac{bh}{2} = \frac{2 cm*4 cm}{2} = 4 cm^{2}$

This polygon does not have an area of 32 cm².

For the rectangle we have:

$A_{r} = bh = 6 cm*4 cm = 24 cm^{2}$

This polygon does not have an area of 32 cm².

For the rectangle trapezoid we have:

$A_{rt} = A_{t} + A_{r} = (4 + 24) cm^{2} = 28 cm^{2}$

So, this polygon does not have an area of 32 cm².

Finally, for the isosceles trapezoid:

$A_{it} = A_{t}*2 + A_{r} = (4*2 + 24) cm^{2} = 32 cm^{2}$

This polygon does have an area of 32 cm².

Therefore, only the isosceles trapezoid has an area of 32 cm².

I hope it helps you!

8 0

3 years ago

Solve the equation of exponential decay.

BabaBlast [244]

Answer:

$9,220,000(0.888)^t

Step-by-step explanation:

Model this using the following formula:

Value = (Present Value)*(1 - rate of decay)^(number of years)

Here, Value after t years = $9,220,000(1 -0.112)^t

Value after t years = $9,220,000(0.888)^t

3 0

4 years ago

10^x • 100^2x = 1000^5. Solve for x, step by step.

babymother [125]

$\bf 10^x\cdot 10^{2x}=1000^5\qquad \boxed{1000=10^3}\qquad 10^x\cdot 10^{2x}=(10^3)^5
\\\\\\
10^{x+2x}=10^{3\cdot 5}\implies 10^{3x}=10^{15}\impliedby 
\begin{array}{llll}
\textit{the bases are the same, thus}\\
\textit{exponents must also}\\
\textit{be the same}
\end{array}
\\\\\\
3x=15\implies x=\cfrac{15}{3}\implies x=5$

3 0

3 years ago

List the integers that satisfy both these inequalities.

alekssr [168]

Answer: -12 < x < $-\frac{9}{2}$

<u>Step-by-step explanation:</u>

2x + 9 < 0 and x > -12

2x < -9

x < $-\frac{9}{2}$

Since it is an "and" statement, x is between -12 and $-\frac{9}{2}$ , so -12 < x < $-\frac{9}{2}$

Graph: -12 o-----------------o $-\frac{9}{2}$

Interval Notation: (-12, $-\frac{9}{2}$ )

8 0

4 years ago