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NeTakaya
3 years ago
9

-t(-4t^3+8t^2)= PLZZ I NEED HELP ASAP ITS WORK FOR KHAN ACADEMY AND I HAVE 6 ASSIGNMENTS TO DO

Mathematics
1 answer:
madreJ [45]3 years ago
8 0
4t4-8t3 is the answer
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Please help with these questions. 20 points if you can solve them with good explanations.​
jeka57 [31]

Answer:

Work shown below!

Step-by-step explanation:

h(x) = -50x + 450

This is a linear function because it is the form y = mx + b

Graph 2 and scenario A and Table 3

g(x) = 4^x

It is a growth in the graph because the slope is positive

Graph 1 and scenario C and Table 1

f(x) = -16x^2 + 1900

It is a decay in the graph because the slope is negative

Graph 3 and scenario B and Table 2

8 0
3 years ago
Read 2 more answers
In the figure,what’s is m
Sergeeva-Olga [200]

Answer:

∠ DBE = 25.5°

Step-by-step explanation:

Given ∠ DBC = 90° and ∠ DBE + ∠ EBC = ∠ DBC, then

∠ DBE = ∠ DBC - ∠ EBC = 90° - 64.5° = 25.5°

7 0
4 years ago
i need help solving the bottom part and filling the letters in the teacher said some spaces and supposed to be blank ​
FromTheMoon [43]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
Select the equation in point-slope form for the line that passes through the point (1, –1) and has a slope of 4.
Dvinal [7]

Answer:

\large \boxed{y + 1 = 4(x - 1)}

Step-by-step explanation:

The point-slope formula for a straight line is

y - y₁= m(x - x₁)

x₁ = 1; y₁ = -1; m = 4  

Substitute the values

\begin{array}{rcl}y - (-1) & = & 4(x - 1)\\y + 1 & = & 4(x - 1)\\\end{array}\\\text{The equation for the line in point-slope form is $\large \boxed{\mathbf{y + 1 = 4(x - 1)}}$}

The figure shows the graph of the equation with slope 4 passing through (1, -1).

7 0
3 years ago
a 13 ft ladder is placed against the side of the building. The bottom of the ladder is 5 ft away from the bottom of the building
puteri [66]
The final answer is x=12
So the ladder will reach 12 feet up

4 0
3 years ago
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