-t(-4t^3+8t^2)= PLZZ I NEED HELP ASAP ITS WORK FOR KHAN ACADEMY AND I HAVE 6 ASSIGNMENTS TO DO

A researcher weighed pumpkins grown across a certain region. The data are rounded to the nearest pound and displayed in this his

icang [17]

Answer:

I think it would be c

Step-by-step explanation:

7 0

2 years ago

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I want to know the answers to the ones circled

LenaWriter [7]

Hello! I will do my best to help you understand and receive the answers.

Let's begin with our first question..

15.) Dao has 2 3/8 pounds of hamburger meat. He is making 1/4 pound burgers. How many burgers can he make?

For this problem we will have to use division. Our equation (use a calculator if needed) is 2 3/8 divided by 1/4 which equals 3.

Your final answer should be : Dao can make 3 hamburgers total.

I would answer the next question, but I believe from this information above you can try and figure it out. If you are still stuck, message me and i can help you from there.

:))

4 0

3 years ago

What is the slope of the line that passes through the points (-2,3) and (-14, -5)?

TEA [102]

Slope = 2/3 (positive 2/3)
You use the formula Y2-Y1/X2-X1 in order to get the slope

8 0

3 years ago

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$

$x=3 \implies 10+3=\$13$

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0

2 years ago

If AB = 4 centimeters, which is closest to BC?

Misha Larkins [42]

Answer:

The correct answer AC = 11.52

Step-by-step explanation:

From the figure attached with this answer shows the triangle ABC.

BC=4 centimeters, m angle B=m angle c, and m angle a = 20 degrees

To find AC

From the figure we can see that D is the mid point and AD⊥BC

Then BD = CD = 4/2 = 2 cm

<BAD = 10° and <CAD = 10°

By using trigonometric ratio,

sin 10 = CD/AC = 2/AC

AC = 2/sin 10 = 2/0.1736 = 11.52

Therefore the value of AC = 11.52 cm

4 0

3 years ago

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