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2 years ago

If x is positive, is

Mathematics

1 answer:

vredina [299]2 years ago

8 0

They are equal.

$\sqrt{\dfrac1{x^2}} = \dfrac1{|x|} = \dfrac1x$

since $x>0$ , and

$\sqrt[3]{\dfrac1{x^3}} = \dfrac1x$

You might be interested in

4/5 rational or irrational

matrenka [14]

Answer: 4/5 IS RATIONAL

Step-by-step explanation: A RATIONAL NUMBER IS A NUMBER THAT CAN BE EXPRESSED AS A FRACTION. IT IS ALREADY A FRACTION SOOOO SÍ POLLO

HOPE THIS HELPS. HAVE A NICE DAY. YOU ARE AMAZING :)

8 0

3 years ago

If one angle of a triangle is 63 and the other two are 7x degrees and 6x degrees what is X worth

Black_prince [1.1K]

Answer:

x = 9

Step-by-step explanation:

Sum of all angles of a triangle = 180

63 + 7x + 6x = 180

63 + 13x =180

13x = 180 - 63

13x = 117

x = 117/13

x = 9

6 0

2 years ago

Read 2 more answers

A pilot traveling 175 miles per hour encounters a head wind of 35 knots. If there are 1.15 knots per mph, what will her true spe

KonstantinChe [14]

Since one knot is 1.15 mph.
We multiply 35 time 1.15, which equals 40.25 mph.
Then we subtract. 175 - 4.25 = 134.75
Round, and you'll get 135mph
Therefore, your answer is 135mph

3 0

3 years ago

Let f be defined by the function f(x) = 1/(x^2+9)

riadik2000 [5.3K]

(a)

$\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}$

Substitute x = 3 tan(t ) and dx = 3 sec²(t ) dt :

$\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt$

$=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}$

(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent p-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

That is, ∑ (-1)ⁿ (n ² + 9)/eⁿ converges absolutely because ∑ |(-1)ⁿ (n ² + 9)/eⁿ| = ∑ (n ² + 9)/eⁿ in turn converges by comparison to a geometric series.

5 0

3 years ago

Deena is planting two rectangular gardens. One garden is 3.67 feet by 8.56 feet, and the other garden is 3.67 feet by 7.45 feet.

Finger [1]

Answer:

A is the correct expression

Step-by-step explanation:

the formula for area of a rectangle is A=WxL

A=area W=width L=length

8.56x3.67=31.42 area of first garden

7.45x3.67=27.34 area of second garden

hope this helps!

have a great day :)

3 0

4 years ago