Given : A florist currently makes a profit of $20 on each of her celebration bouquets and sells an average of 30 bouquets every week . and graph
To Find : Maximum profit , breakeven point , profit interval
Solution:
The maximum profit the florist will earn from selling celebration bouquets is $ 675
peak of y from Graph
The florist will break-even after Selling 20 one-dollar decreases.
at breakeven
Break even is the point where the profit p(x) becomes 0
The interval of the number of one-dollar decreases for which the florist makes a profit from celebration bouquets is (0 ,20).
after 20 , P(x) is - ve
Answer:
The answer to your question is number 3.
Step-by-step explanation:
Data
slope = m = 2
Point = (3, 9)
Process
1.- Write the equation of the line in the form point-slope
y - y1 = m(x - x1)
2.- Identify the values of x1 and y1
x1 = 3 y1 = 9
3.- Substitution
y - 9 = 2(x - 3)
4.- Simplify
y - 9 = 2x - 6
y = 2x - 6 + 9
5.- Result
y = 2x + 3 slope y-intercept form
Answer:
y = - 8 x + 2
Step-by-step explanation:
Use any two pairs to find the slope with
slope = (y2-y1)/(x2-x1)
for example: (0, 2), and (1, -6)
slope = (- 6 - 2) / (1 - 0) = - 8
so the equation should look like:
y = -8 x + b
use point (0, 2) to find b:
2 = - 8 (0) + b
b = 2
Then
y = - 8 x + 2
I think it's a home loan from old home owners idk if this will help
Answer:
D
Step-by-step explanation:
We know that vector addition is scalar addition.
Given vectors are u = <-3.5, -1.5> and v = <-1.25, 2.25>
2v = < -2.5, 4.5>
2v - u = < -2.5, 4.5> - <-3.5, -1.5> = < -2.5 - (-3.5) , 4.5 -(-1.5) >
2v-u = < 1 , 6 >
This vector is basically i + 6j which is drawn in option D
