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svetoff [14.1K]

1 year ago

10

How do you this .. I don’t know how to do it

1 answer:

IRISSAK [1]1 year ago

7 0

I would help but your missing parts of the problem

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Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.

natka813 [3]

Suppose that the height (in centimeters) of a candle is a linear function of

the amount of time (in hours) it has been burning.

Let x be the amount of time in hours

Let y be the heoght of a candle in centimeters

The two points are then as (9,24.5) and (23,17.5).

$\mathrm{Find\:the\:line\:}\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(9,\:24.5\right)\mathrm{,\:}\left(23,\:17.5\right)$

$\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(9,\:24.5\right),\:\left(x_2,\:y_2\right)=\left(23,\:17.5\right)$

$m=\frac{17.5-24.5}{23-9}$

$m=-0.5$

$\mathrm{Plug\:the\:slope\:}-0.5\mathrm{\:into\:}y=mx+b$

$y=\left(-0.5\right)x+b$

$\mathrm{Plug\:in\:}\left(9,\:24.5\right)\mathrm{:\:}\quad \:x=9,\:y=24.5$

$24.5=\left(-0.5\right)\cdot \:9+b$

$24.5=\left(-0.5\right)\cdot \:9+b$

$-4.5+b=24.5$

$b=29$

$\mathrm{Construct\:the\:line\:equation\:}\mathbf{y=mx+b}\mathrm{\:where\:}\mathbf{m}=-0.5\mathrm{\:and\:}\mathbf{b}=29$

$y=-0.5x+29$

Now plug in x=21, we get

$y=-0.5*21+29=18.5$

Thus the height of the candle after 21 hours is 18.5 centimeters.

7 0

3 years ago

Which numbers are written in scientific notation? Check all that apply.

____ [38]

Answer:

$2.7 \times 10^{ - 3}$

$6.1 \times 10^{5}$

$9.582 \times 10^{6}$

Step-by-step explanation:

-

4 0

2 years ago

Solve for y.<br> 3x + 4y = z<br> -----------------

Georgia [21]

Answer:

y= z-3x/4

Step-by-step explanation:

4y=z-3x

y=z-3x/4

3 0

3 years ago

If there are 205 students in the school, which is the best estimate of the number of students that are in the 5th grade?

Mila [183]

Answer:

34 people

Step-by-step explanation:

8 0

2 years ago

Let mu denote the true average number of minutes of a television commercial. Suppose the hypothesis H0: mu = 2.1 versus Ha: mu &

natka813 [3]

Answer:

A. T > 2.539

Step-by-step explanation:

We have a hypothesis test of the mean, with unknown population standard deviation.

The hypothesis are:

$H_0: \mu = 2.1 \\\\H_a: \mu > 2.1$

From the hypothesis we can see that the test is right-tailed, so the critical value of t should be a positive value.

The degrees of freedom can be calculated as:

$df=n-1=20-1=19$

The significance level is 0.01, so the critical value tc should be the one that satisfies:

$P(t>t_c)=0.01$

Looking up in a t-table, for 19 degrees of freedom, this critical value is tc=2.539.

7 0

3 years ago