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1 year ago

How do you this .. I don’t know how to do it

Mathematics

1 answer:

IRISSAK [1]1 year ago

7 0

I would help but your missing parts of the problem

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Solve x 2 - x - 5/2 = 0 using the quadratic formula.

rewona [7]

Answer:

your answer would be: x=1±√11 all divided by 2

Hope this helps

~QueenSupreme AKA Trinity

6 0

3 years ago

Read 2 more answers

What is m∠B? (view attached file)

Pepsi [2]

Answer:

m∠B = 141°

Step-by-step explanation:

sides of polygon (n) = 7

sum of angles of polygon = {(n - 2) * 180°}

= {(7 -2)*180°}

= 5* 180°

= 900°

Now,

m∠B = 900° - 148° - 142° - 130° - 129° - 120° - 90°

m∠B = 141°

4 0

2 years ago

Given the function g(x) = (x + 3)^2. Martin says the graph should be translated right 3 units from the parent graph f(x) = x^2.

oksano4ka [1.4K]

Answer:

Martin is wrong because in the Graph we can clearly see that the graph will be translated left 3 unit from the parent graph. The vertex point will be (-3,0)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Can someone please help me on this!!

Rufina [12.5K]

You need help with all of them or one in specific?

6 0

3 years ago

Condense the following logs into a single log:

mamaluj [8]

QUESTION 1

The given logarithm is

$8\log_g(x)+5\log_g(y)$

We apply the power rule of logarithms; $n\log_a(m)=\log_(m^n)$

$=\log_g(x^8)+\log_g(y^5)$

We now apply the product rule of logarithm;

$\log_a(m)+\log_a(n)=\log_a(mn)$

$=\log_g(x^8y^5)$

QUESTION 2

The given logarithm is

$8\log_5(x)+\frac{3}{4}\log_5(y)-5\log_5(z)$

We apply the power rule of logarithm to get;

$=\log_5(x^8)+\log_5(y^{\frac{3}{4}})-\log_5(z^5)$

We apply the product to obtain;

$=\log_5(x^8\times y^{\frac{3}{4}})-\log_5(z^5)$

We apply the quotient rule; $\log_a(m)-\log_a(n)=\log_a(\frac{m}{n} )$

$=\log_5(\frac{x^8\times y^{\frac{3}{4}}}{z^5})$

$=\log_5(\frac{x^8 \sqrt[4]{y^3} }{z^5})$

7 0

2 years ago