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ANEK [815]
2 years ago
7

Is it A. x= _ b.the solution is all real numbers c.there is no solution

Mathematics
1 answer:
Gemiola [76]2 years ago
8 0

The value of x in the equation is - 3.

<h3>How to find the  variable in an equation?</h3>

Variables are number represented by a letter in an equation.

Therefore,

-5x - 9 = 2x  + 12

subtract 12 from both sides of the equation

-5x - 9 = 2x  + 12

-5x - 9 - 12 = 2x  + 12 - 12

-5x - 21 = 2x

add 21 to both sides of the equation

-5x - 21 = 2x

-5x  - 21 + 21 = 2x + 21

-5x = 2x + 21

subtract 2x from both sides

-5x = 2x + 21

-5x - 2x = 2x -2x + 21

-7x = 21

divide both sides by -7

-7x / -7 = 21 / - 7

x = -3

learn more on equation here: brainly.com/question/7421811

#SPJ1

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The Whisky Rebellion:
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Step-by-step explanation:

7 0
3 years ago
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Kiran and Mai are trying to figure out if this equation is an identity, what do you think
ValentinkaMS [17]

Expanding the left side of the equation, it is found that since <u>both sides are equal</u>, yes, it is an identity.

An equality represents an identity if <u>both sides are equal</u>.

In this problem:

(a - b)^4 = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4

Expanding the left side:

(a - b)^2(a - b)^2 = a^4 - 4a^3b + 6a^2b^2 + 4ab^3 + b^4

(a^2 - 2ab + b^2)(a^2 - 2ab + b^2) = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4

a^4 - 4a^3b + + 6a^2b^2 - 4ab^3 + b^4 = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4

Since <u>both sides are equal</u>, yes, it is an identity.

A similar problem is given at brainly.com/question/24866308

7 0
3 years ago
Explain. this to me i do not understand
Wittaler [7]
You just simply divide. 
836 divided by 44.
=19

6 0
3 years ago
Could use some help on this please
vfiekz [6]

Answer:

x = 15, y = 4

Step-by-step explanation:

To solve this, we have to define the triangles first. Since the triangles are congruent by HL, it means that the hypotenuse and the leg of the triangle are defined to be equal. By flipping one of the triangles upsidedown, we can visualize the hypotenuse of the triangles and the leg of the triangles (which are equal).

The two equations are the following:

x + 1 = 4y

x = y + 11

If I add 1 to both sides of the second equation, I get the following equation:

x + 1 = y + 11 + 1 = y + 12

By comparing this new equation with the first one, we will get:

x + 1 = 4y = y + 12

We can ignore x+1 for now since y can not be solved.

4y = y + 12

By subtracting both sides of this equation by y, we will get.

3y = 12

This solves for y, where

y = 4

Now, we can re-use one of the equations, which is

x = y + 11

Now that we know y is 4, we can plug it into this equation.

x = 4 + 11 = 15

4 0
3 years ago
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