We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
5 oranges
Step-by-step explanation:
to solve this problem we need to make a cross-multiplication equation
2.34 is to 6 as 1.95 is to ?
? is the number of oranges that are needed to be found that were bought
2.34/6 = 1.95/?
Now we cross multiply 6 and 1.95 = 11.7
11.7/2.34 = 5
Give brainliest, please!
hope this helps :)
Y= Slope(x) + y-int.
Y= mx +b
Y= -3x +2
Answer:
The answer is A.
Step-by-step explanation:
Lets call f(x)=y, so y= 4*(3*x-5), we want to find 'x', using 'y' as a the variable.

Now lets change the name of 'y' to 'x', and 'x' to f^-1(x).
f-1(x) = (x+20)/12