Find the slope of the line that passes through (3, -1) and (4, 7)

Mathematics

2 answers:

otez555 [7]2 years ago

6 0

The slope is 4 or 8/2

Mrac [35]2 years ago

5 0

Answer:

Written in slope-intercept form.

y = mx + b

The answer to your question would be

m = 8

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Pavlova-9 [17]

$\boxed{\sf 11, 7}\boxed$

Isolate this variable, x, by dividing each side by factors that do not contain the variable.

6 0

2 years ago

Triangle ABC is shown on the graph below. c. Triangle ABC is translated 1 unit right and 2 units down what are the coordinates o

ruslelena [56]

The translation would be written as (x, y)→(x+1, y-2). A would be mapped to A'(2, 1); B would be mapped to B'(5, 3); and C would be mapped to C'(4, -1).

For each ordered pair, you would add 1 to the x-coordinate and subtract 2 from the y-coordinate.

6 0

2 years ago

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nordsb [41]

Answer: 72yd^2

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Use the bionomial theorem to write the binomial expansion

MaRussiya [10]

Answer:

$\left(\frac{x}{2} + 3 y\right)^{4}=\frac{x^{4}}{16} + \frac{3}{2} x^{3} y + \frac{27}{2} x^{2} y^{2} + 54 x y^{3} + 81 y^{4}$

Step-by-step explanation:

$\left(\frac{1}{2}x+3y \right)^4=\left(\frac{x}{2}+3y \right)^4\\$

Binomial Expansion Formula:

$(a+b)^n=\sum_{k=0}^n \binom{n}{k} a^{n-k} b^k$ , also $\binom{n}{k}=\frac{n!}{(n-k)!k!}$

We have to solve $\left(\frac{x}{2} + 3 y\right)^{4}=\sum_{k=0}^{4} \binom{4}{k} \left(3 y\right)^{4-k} \left(\frac{x}{2}\right)^k$

Now we should calculate for $k=0, k=1, k=2, k=3 \text{ and } k =4;$

First, for $k=0$

$\binom{4}{0} \left(3 y\right)^{4-0} \left(\frac{x}{2}\right)^{0}=\frac{4!}{(4-0)! 0!}\left(3 y\right)^{4} \left(\frac{x}{2}\right)^{0}=\frac{4!}{4!}(81y^4)\cdot 1 =81 y^{4}$