All categories

2 years ago

Please find me the value of x

Mathematics

2 answers:

ipn [44]2 years ago

7 0

Answer:

x = 60°

Step-by-step explanation:

∠ ABO and ∠ CBO are a linear pair and sum to 180° , that is

∠ ABO + ∠ CBO = 180°

150° + ∠ CBO = 180° ( subtract 150° from both sides )

∠ CBO = 30°

∠ XYO and ∠ CBO are alternate angles and are congruent , so

∠ XYO = 30°

∠ XOY and ∠ COY are a linear pair and sum to 180° , then

∠ XOY + ∠ COY = 180°

∠ XOY + 90° = 180° ( subtract 90° from both sides )

∠ XOY = 90°

the sum of the 3 angles in Δ XOY = 180° , that is

x + 90° + 30° = 180°

x + 120° = 180° ( subtract 120° from both sides )

x = 60°

erastova [34]2 years ago

4 0

Answer:

x = 60°

Step-by-step explanation:

See picture below. When two parallel lines are cut by a transversal there are some special relationships.

You might be interested in

And an electronics warehouse ships TVs and DVD players to retailers all throughout the United States. The weight of three televi

vodomira [7]

X= weight of TV
y= weight of CD

3x+5y= 62.5
3x+ 2y= 52
You can either solve for a variable, or eliminate a variable by subtracting the second equation from the first:

3x + 5y = 62.5
-(3x+2y = 52)
0 + 3y = 10.5, so y = 10.5/3 or 3.5.

Now plug y= 3.5 back into any equation to get x:

3x + 5(3.5) = 62.5
3x + 17.5 = 62.5
3x = 45
x = 15
Always check work. Both equations should be true for x=15, y= 3.5

4 0

2 years ago

A pitcher of orange juice is made from a can of frozen orange juice by mixing 3 ounces of frozen juice with 5 ounces of water. H

ziro4ka [17]

3:5
6:10
9:15
12:20

12 ounces

7 0

3 years ago

Alexander makes a model of the Great Pyramid of Giza with the dimensions shown.

Leviafan [203]

Answer:

The area of the square base is 100 in.2.

The area of each triangular face is 40 in.2.

Alexander will need 260 in.2 of paint.

Step-by-step explanation:

I dan't have an explanation I just guessed.

7 0

3 years ago

Piz help me!!!! <img src="https://tex.z-dn.net/?f=look%20%5C%3A%20at%20%5C%3A%20pic%20%5C%3A%20piz" id="TexFormula1" titl

s344n2d4d5 [400]

Here is my solution to this question worked out on paper:

7 0

3 years ago

77. the volume of a cube is increasing at a rate of <img src="https://tex.z-dn.net/?f=10%20%5Cmathrm%7B~cm%7D%5E%7B3%7D%20%2F%20

Colt1911 [192]

Answer:

$\displaystyle \frac{4}{3}\text{cm}^2/\text{min}$

Step-by-step explanation:

Given

$\displaystyle \frac{dV}{dt}=10\:\text{cm}^3/\text{min}\\ \\V=s^3\\\\SA=6s^2\\\\\frac{d(SA)}{dt}=?}\:;s=30\text{cm}$

Solution

(1) Find the rate of the cube's edge length with respect to time at s=30:

$\displaystyle V=s^3\\\\\frac{dV}{dt}=3s^2\frac{ds}{dt}\\ \\10=3(30)^2\frac{ds}{dt}\\ \\10=3(900)\frac{ds}{dt}\\\\10=2700\frac{ds}{dt}\\\\\frac{10}{2700}=\frac{ds}{dt}\\\\\frac{ds}{dt}=\frac{1}{270}\text{cm}/\text{min}$

(2) Find the rate of the cube's surface area with respect to time at s=30:

$\displaystyle SA=6s^2\\\\\frac{d(SA)}{dt}=12s\frac{ds}{dt}\\ \\\frac{d(SA)}{dt}=12(30)\biggr(\frac{1}{270}\biggr)\\\\\frac{d(SA)}{dt}=\frac{360}{270}\biggr\\\\\frac{d(SA)}{dt}=\frac{4}{3}\text{cm}^2/\text{min}$

Therefore, the surface area increases when the length of an edge is 30 cm at a rate of $\displaystyle \frac{4}{3}\text{cm}^2/\text{min}$ .

6 0

2 years ago

Please find me the value of x​

Please find me the value of x