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vodka [1.7K]
3 years ago
15

At a local Chamber of Commerce, there are 8 men and 7 women present for an executive election of a president, vice-president and

treasurer. Determine the probability that a women will be elected into one of the executive positions.
Mathematics
1 answer:
Otrada [13]3 years ago
7 0
Given that the are 8 men and 7 women present for an election, the probability that a woman will be elected will be given by:
P(Electing a woman)=[Total number of women]/[total number of candidates]
=7/15
the answer is 7/15
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the answer is A&d

Step-by-step explanation:

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Solve the simultaneous equation x^2-4y^2=9 and x+2y=1​
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x=5,y=-2

Step-by-step explanation:

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There are 5 boys and 4 girls in my class. All of them are distinguishable. In how many ways can they be seated in a row of 9 cha
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3 years ago
Calculate the allele frequencies in this population of palm trees. A model consisting of a box containing fourteen, randomly arr
bogdanovich [222]

Answer:

The correct answer is

0.5 F, 0.5 f

Step-by-step explanation:

We note the following

Number of colored circles in the box = 14

Number of red circles in the box = 4

Number of purple circles in the box = 6

Number of blue circles in the box = 4

The allele frequency are as follows

Where the frequency is given as

Genotype            Frequency                         Relative frequency        

FF = Red                    4                                       4/14 (0.29≈0.3)                  

Ff = Purple                 6                                       6/14 (0.43≈0.4)

ff = Blue                     4                                       4/14(0.29≈0.3)

Within this population,

We however  have 4 FF = 8 F

                                6 Ff =   6 F + 6 f  and

                                4 ff = 8 f

Total allele = 8+6+6+8 = 28

Relative frequency of F = (8+6)/28 = 14/28 = 0.5

relative frequency of f = (8+6)/28 = 0.5

Therefore the allele frequencies in the palm tree population is

0.5 F, 0.5 f

When in equilibrium we have

However the FF has the product of F×F which is = F² = 0.29 so the frequency of F = √(0.29) = 0.535≈ 0.5

The frequency of Ff is Ff or fF =  0.43 since there is equal number of each allele in Ff we have fF or Ff = Ff = 0.43

Which hives 0.43/2 = F =f ≈ 0.2

To  

and ff = 0.29 so that f = 0.535 ≈ 0.5

Therefore f = F  = 0.5 + 0.2 = 0.7

5 0
3 years ago
Could the equation. For the graph of the function have degree 4?explain
aivan3 [116]

The graphed polynomial seems to have a degree of 2, so the degree can be 4 and not 5.

<h3>Could the graphed function have a degree 4?</h3>

For a polynomial of degree N, we have (N - 1) changes of curvature.

This means that a quadratic function (degree 2) has only one change (like in the graph).

Then for a cubic function (degree 3) there are two, and so on.

So. a polynomial of degree 4 should have 3 changes. Naturally, if the coefficients of the powers 4 and 3 are really small, the function will behave like a quadratic for smaller values of x, but for larger values of x the terms of higher power will affect more, while here we only see that as x grows, the arms of the graph only go upwards (we don't know what happens after).

Then we can write:

y = a*x^4 + c*x^2 + d

That is a polynomial of degree 4, but if we choose x^2 = u

y = a*u^2 + c*u + d

So it is equivalent to a quadratic polynomial.

Then the graph can represent a function of degree 4 (but not 5, as we can't perform the same trick with an odd power).

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ1

5 0
2 years ago
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