Answer:
48f^2-110f+63
Step-by-step explanation:
We multiple every part of first sum with every prt of the 2nd sum:
(6f-7)(8f-9)=48f^2-54f-56f+63=
48f^2-110f+63
Step-by-step explanation:
sum of the arithmetic sequence
a1 = 8
a2 = a1 + 8 = 8+8 = 16
...
an = 8×n
the sum of the first n elements of such a series is
n/2 × (2×a1 + (n - 1)×d]
with d being the difference between 2 consecutive elements (= the added constant).
so,
s30 = 30/2 × (2×8 + 29×8) = 15×(31×8) = 3720
Plus a negative value becomes subtraction:
-12 + -23 = -12 -23 = -35
Quotient is the answer of the division
0.4/0.01 = 40 x 10 = 4/0.1 = 40 x 10 = 40/1 = 40
