F(x) = x (x^3 - x^2 + x + 1)
Answer:
basketball= 66.66 infinite%
baseball=42.86%
Step-by-step explanation:
if you divide 14 by 21 you get .66 infinite which is 66.66 infinite%
divide 9 by 21 you get around .4286 which is 42.86%
Answer:
23. 0.4583 seconds
24. 0.0107 seconds
Step-by-step explanation:
The problem statement tells you how to work it. You need to convert speed from miles per hour to feet (or inches) per second.
90 mi/h = (90·5280 ft)/(3600 s) = 132 ft/s = (132·12 in)/s = 1584 in/s
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23. The time it takes for the ball to travel 60.5 ft is ...
time = distance/speed
time = (60.5 ft)/(132 ft/s) = 0.4583 s
It takes 458.3 milliseconds to reach home plate.
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24. time = distance/speed
time = (17 in)/(1584 in/s) = 0.0107 s
The ball is in the strike zone for 10.7 milliseconds.
Answer:
sorry i wish i knew how but i would like to give you aomething other than an answer for your question and i hope this is ok.
Step-by-step explanation:
every day is a new day and a new opportunity to change the world no matter how BIG or how small. even if you make mistakes. always remember this though. whatever you put into the world, whether it be good or bad, it will always come back three times.
meaning that when you do something good something three times as good will happen to you. The same is so for bad except it would be 3 times as bad as will happen to you. I hope your day is great and may you do many great things.
In statistics, a Chi-squared test may be used to determine holiday choice and gender and α (alpha) is the response variable.
<h3>What is the Chi-squared test? </h3>
A statistical technique called the chi-square test is used to compare actual outcomes with predictions.
The goal of this test is to establish if a discrepancy between actual and predicted data is the result of chance or a correlation between the variables you are researching.
Whether there is a statistically significant association between categorical variables is determined by the Chi-square test of independence.
This issue is addressed by a hypothesis test. The chi-square test of association is another name for this assessment.
Hence,in stats would a test looking at gender & holiday preference yes you can do a Chi-squared test and α(alpha) is the response variable.
To learn more about the Chi-squared test refer;
brainly.com/question/14082240
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