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NemiM [27]
2 years ago
5

an isosceles triangle has integer side lengths and perimeter 25. what is the sum of all possible lengths of the leg

Mathematics
1 answer:
scZoUnD [109]2 years ago
7 0

All the possible integer values for the equal sides and third length of the  isosceles triangle are;

2, 2, 21

3, 3, 19

5, 5, 15

7, 7, 11

11, 11, 3

<h3>What is the dimension of the Isosceles Triangle?</h3>

An isosceles triangle has two equal sides only.

The possible prime numbers here are 2, 3, 5, 7, 11.

Now, we don’t whether the prime number sides are equal, but let’s assume that they are. Thus, this means that we could have the dimesions as;

2, 2, 21

3, 3, 19

5, 5, 15

7, 7, 11

11, 11, 3

All the above are all possible integer values for the equal sides and third length of the  isosceles triangle

Read more about isosceles triangle at; brainly.com/question/1475130

#SPJ1

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3 years ago
An open metal tank of square base has a volume of 123 m^3
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Answer:

  a) h = 123/x^2

  b) S = x^2 +492/x

  c) x ≈ 6.27

  d) S'' = 6; area is a minimum (Y)

  e) Amin ≈ 117.78 m²

Step-by-step explanation:

a) The volume is given by ...

  V = Bh

where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:

  123 = x^2·h

  h = 123/x^2

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b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.

S=x^2+Ph=x^2+(4x)\dfrac{123}{x^2}\\\\S=x^2+\dfrac{492}{x}

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c) The derivative of the area with respect to x is ...

S'=2x-\dfrac{492}{x^2}

When this is zero, area is at an extreme.

0=2x -\dfrac{492}{x^2}\\\\0=x^3-246\\\\x=\sqrt[3]{246}\approx 6.26583

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d) The second derivative is ...

S''=2+\dfrac{2\cdot 492}{x^3}=2+\dfrac{2\cdot 492}{246}=6

This is positive, so the value of x found represents a minimum of the area function.

__

e) The minimum area is ...

S=x^2+\dfrac{2\cdot 246}{x}=(246^{\frac{1}{3}})^2+2\dfrac{246}{246^{\frac{1}{3}}}=3\cdot 246^{\frac{2}{3}}\approx 117.78

The minimum area of metal used is about 117.78 m².

3 0
3 years ago
Find the minimum, maximum, and range for the given set of data.
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It’s A

You take the smallest number for min
And largest number for max
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7 0
4 years ago
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Answer:

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Step-by-step explanation:

Hope this helps! :3

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trapecia [35]

C.) x = -4 is the correct answer

Step-by-step explanation:

In order to solve the equation we have to isolate x on one side of equation

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7x + 6 = -22

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Dividing both sides by 7

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Hence,

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Keywords: Linear equation

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