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Ulleksa [173]
3 years ago
5

Someone pls help ASAP!! :)

Mathematics
2 answers:
suter [353]3 years ago
4 0

Product of indice find  (y⁴)³

lyudmila [28]3 years ago
4 0

Answer:

Step-by-step explanation:

x = 90° {right angle}

y = 38° {similar angle}

w = 180 - (90+38){sum of angle 180°}

w = 180 - 128

w = 52°

u = 6.2yds

z = 10yds

v = 7.9yds

You might be interested in
What’s are the answers for both?
nevsk [136]

Answer:

<h2>d = 8</h2><h2>g = 2</h2>

Step-by-step explanation:

8d + 4 = 5d + 28

Group like terms

That's

8d - 5d = 28 - 4

3d = 24

Divide both sides by 3

d = 8

\frac{7(7g + 8)}{4}  = 38.5

Cross multiply

we have

7(7g + 8) = 38.5(4)

49g + 56 = 154

49g = 154 - 56

49g = 98

Divide both sides by 49

g = 2

Hope this helps you

5 0
4 years ago
A. Analyze the number of dark triangles. Describe the pattern.​
Kamila [148]
We need a picture to answer this...
3 0
4 years ago
Get Ready, Set
postnew [5]
Wait is this a anime? Can you tell what anime is please?
3 0
3 years ago
Read 2 more answers
Help me please<br>help.me​
levacccp [35]

Answer:

The answers of the questions are given below :

  • a) = 4096
  • b) = 1.25
  • 3) = m²
  • 4) = r⁴s³
  • 5) = a⁸/b¹²

Step-by-step explanation:

\large{\tt{\underline{\underline{\red{QUESTION}}}}}

\begin{gathered}\footnotesize\boxed{\begin{array}{c|c|c}\bf\underline{Given}&\bf\underline{Solution}&\bf{\underline{Simple\: Form}}\\\\\rule{60pt}{0.5pt} &\rule{70pt}{0.5pt}& \rule{70pt}{0.5pt}\\\\ 1.\: {4}^{6} & & \\\\ 2.\: \bigg(\dfrac{2^6}{5^3} \bigg)& &\\\\  3. \: \Big({m}^{\frac{2}{3}}\Big)\bull \Big({m}^{\frac{4}{3}}\Big) & &\\\\4. \:  \big({r}^{12} {s}^{9}\big)^{ - \frac{1}{3}} &&\\\\ 5.\bigg(\dfrac{a^4}{a^6}\bigg)^{2}& &\end{array}}\end{gathered}

\begin{gathered}\end{gathered}

\large{\tt{\underline{\underline{\red{SOLUTION}}}}}

Question. 1

>> 4⁶

\begin{gathered}\qquad{= 4 \times 4 \times 4 \times 4 \times 4 \times 4} \\  \qquad{= 16 \times 4 \times 4 \times 4 \times 4} \\ \qquad{= 64 \times 4 \times 4 \times 4} \\ \qquad{= 256\times 4 \times 4} \\ \qquad{= 1024  \times 4} \\ \qquad{= 4096} \end{gathered}

  • Hence, the answer is 4096.

\begin{gathered}\end{gathered}

Question. 2

>> (2⁶/5³)^-⅓

\begin{gathered} \qquad\implies{\bigg(\frac{2^6}{5^3}\bigg)^{ - \frac{1}{3}}}\\  \\ \qquad\implies{\bigg(\frac{64}{125}\bigg)^{ - \frac{1}{3}}}\\  \\\qquad\implies{\bigg( \frac{1}{\frac{64}{125}}\bigg)^{ \frac{1}{3}}} \\  \\ \qquad\implies{\bigg( 1 \times  \frac{125}{64} \bigg)^{ \frac{1}{3}}} \\  \\ \qquad\implies{\bigg( \frac{125}{64} \bigg)^{ \frac{1}{3}}} \\  \\\qquad\implies{\bigg( \sqrt[3]{ \frac{125}{64}}\bigg)}  \\  \\ \qquad\implies{\bigg( \dfrac{5}{4} \bigg)} \\  \\ \qquad\implies{\Big( 1.25\Big)}\end{gathered}

  • Hence, the answer is 1.25.

\begin{gathered}\end{gathered}

Question. 3

>> (m^2/3)•(m^4/3)

\begin{gathered} \qquad{=  \Big({m}^{\frac{2}{3}}\Big) \bull \Big({m}^{ \frac{4}{3}}\Big)} \\  \\ \qquad{=  \Big({m}^{\frac{2}{3} +  \frac{4}{3}}\Big)} \\  \\ \qquad{=  \Big({m}^{\frac{2 + 4}{3}}\Big)} \\  \\ \qquad{=  \Big({m}^{\frac{6}{3}}\Big)} \\  \\ \qquad{=  \Big({m}^{2}\Big)}\end{gathered}

  • Hence, the answer is m².

\begin{gathered}\end{gathered}

Question. 4

>> (r¹² s⁹)^⅓

\begin{gathered} \qquad\implies{\Big( {r}^{12} \: {s}^{9}\Big)^{\frac{1}{3}}}\\\\ \qquad\implies{\Big({r}^{\frac{12}{3} } \: {s}^{\frac{9}{3}}\Big)}  \\  \\ \qquad\implies{\Big({r}^{\cancel{\frac{12}{3}}} \: {s}^{\cancel{\frac{9}{3}}}\Big)}  \\  \\ \qquad\implies{\Big({r}^{4} \: {s}^{3}\Big)} \end{gathered}

  • Hence, the answer is r⁴s³.

\begin{gathered}\end{gathered}

Question. 5

>> (a⁴/b⁶)^2

\begin{gathered} \qquad{ =  \Big(\frac{a^4}{b^6}\Big)^{2}} \\ \\  \qquad{ =  \Big(\frac{a^{4 \times 2}}{b^{6 \times 2}}\Big)} \\ \\ \qquad{ =  \Big(\frac{a^{8}}{b^{12}}\Big)} \end{gathered}

  • Hence, the answer is a⁸/b¹².

\underline{\rule{220pt}{3pt}}

4 0
2 years ago
Find the standard form of the equation of the parabola with a focus at (-2, 0) and a directrix at x = 2.
Leokris [45]
Standard form is, hold a sec

x=2 is directix
that means it opens left or right
so we must use
(y-k)²=4p(x-h)
where vertex is (h,k) and p is distance from focus to vertex
also shortest distance from vertex to directix
the shortest distance from focus to directix is 2p
if p>0 then the parabola opens right
if p<0 then pareabola opens left

so
(-2,0) and x=2
the distance is 4
4/2=2
p=2
wait, positive or negative
focus is to the left of the directix so p is negative
p=-2

vertex is 2 to the right of the focus and 2 to the left of directix
vertex is (0,0)

so
(y-0)²=4(-2)(x-0) or
y²=-8x is da equation
not sure what form is standard tho
4 0
3 years ago
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