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elixir [45]
3 years ago
14

The equation of a parabola is given. y=34x2−6x+15

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
7 0
The x coordinate of the vertex = -b/2a  = -(-6) / 2*34  = 0.08824

y coordinate = 34(0.08824^2 - 6(0.08824) + 15 =  14.735

so its (0.088, 14.735)     correct to 3 decimal places

lutik1710 [3]3 years ago
7 0

Answer:

A quadratic equation is in the form of  y=ax^2+bx+c,....[1] then the axis of symmetry is given by:

x = -\frac{b}{2a}

Vertex of the function is given by:

\text{vertex} = (-\frac{b}{2a}, f(-\frac{b}{2a}))

As per the statement:

Given the function:

y=f(x)=34x^2-6x+15        ....[2]

Compare this with equation [1] we have;

a = 34 and b = -6

then;

x = -\frac{-6}{2(34)}

⇒x =\frac{6}{68}=0.088252941

⇒x =0.08825294

Substitute the value of x in [2] we have;

f(0.08825294)=34(0.08825294)^2-6(0.08825294)+15

f(0.08825294)=0.264705882-0.529411765+15

Simplify:

f(0.08825294)=14.7352941

⇒Vertex = (0.08825294,14.7352941)

Therefore, the coordinate of the vertex of the parabola is, (0.08825294,14.7352941)

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