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maxonik [38]
3 years ago
13

which expression is irrational the square root of 2 the square root of 4 the square root of 484 the square root of 529

Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0
If i try i think its the square root of 2 is irrational...
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70 points!!!! Find the horizontal and the vertical components of f.
choli [55]

Answer:

  • F = (16.74, -2.95)

Explanation:

<u />

<u>1) Horizontal component</u>

The horizontal component is related to the magnitude of the force by the cosine ratio:

  • cos (α) = Fx / | F |

Where α in the angle (-10º), Fx is the horizontal component, and | F | is the magnitude of the force (17).

  • cos(-10º) = Fx / 17 ⇒ Fx = cos (-10º) × 17 = 16.74

<u />

<u>2) Vertical component</u>

The vertical component is related to the magnitude of the force by the sine ratio:

  • sin (α) = Fy / | F |

Where α in the angle (-10º), Fy is the vertical component, and | F | is the magnitude of the force (17).

  • sin(-10º) = Fy / 17 ⇒ Fy = sin (-10º) × 17 = -2.95

<u />

<u>3) Form (x,y)</u>

  • F = (16.74, -2.95)
6 0
3 years ago
The perimeter of a rectangle is 44 inches. If the width of the rectangle is four more than half the length, find the length of t
Mars2501 [29]

Answer: the length of the rectangle is 12 inches

Step-by-step explanation:

Let the length of the rectangle is x inches

Hence, the width is (x/2)+4 inches

Thus,

\displaystyle\\2(x+(\frac{x}{2} +4))=44\\\\2x+x+8=44\\\\3x+8=44\\\\3x+8-8=44-8\\\\3x=36\\

Divide both parts of the equation by 3:

x=12\ inches

6 0
1 year ago
If X1 = 440, Y1 = 220, and X2 = 360, what’s the value of Y2
sergeinik [125]

Answer:

140 is the answer for y2 because x1 is 80 more than x2 so you would subtract y2 by 80

8 0
2 years ago
Help!!?????? Plssssss
zhannawk [14.2K]

Answer:

1st row- 27

2nd row- 18, 48

3rd row- 55

8 0
3 years ago
Read 2 more answers
F(x) = 2/x, g(x) = |x| -1 <br><br><br> What is the domain of (fog) (x)?<br><br> will mark brainliest
brilliants [131]

Answer:

x≠-1,1

Step-by-step explanation:

f(g(x)) is a composition where g(x) is is substituted for x in f(x).

Recall, f(x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.

|x|-1=0

|x|=1

x=1,-1

3 0
3 years ago
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