<span>r²sin²θ = 16rcosθ </span>
<span>rsin²θ = 16cosθ </span>
<span>r = 16cosθ / sin²θ </span>
<span>r = 16cotθcscθ</span>
I hope it workssssssssssssssssssssss.
Answer:
hundredths
Step-by-step explanation:
Answer:
11.44% probability that exactly 12 members of the sample received a pneumococcal vaccination.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they received a pneumococcal vaccination, or they did not. The probability of an adult receiving a pneumococcal vaccination is independent of other adults. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
70% of U.S. adults aged 65 and over have ever received a pneumococcal vaccination.
This means that ![p = 0.7](https://tex.z-dn.net/?f=p%20%3D%200.7)
20 adults
This means that ![n = 20](https://tex.z-dn.net/?f=n%20%3D%2020)
Determine the probability that exactly 12 members of the sample received a pneumococcal vaccination.
This is P(X = 12).
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 12) = C_{20,12}.(0.7)^{12}.(0.3)^{8} = 0.1144](https://tex.z-dn.net/?f=P%28X%20%3D%2012%29%20%3D%20C_%7B20%2C12%7D.%280.7%29%5E%7B12%7D.%280.3%29%5E%7B8%7D%20%3D%200.1144)
11.44% probability that exactly 12 members of the sample received a pneumococcal vaccination.
Answer:
16/13
Step-by-step explanation:
Multiple inverse for 13/16 is 16/13