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Vitek1552 [10]
3 years ago
10

A standard six sided dice is rolled. What is te probability of rolling a 3 OR a 5

Mathematics
2 answers:
Vikki [24]3 years ago
5 0

Answer:

1/3

Step-by-step explanation:

Rolling a die has the possible outcomes of 1,2,3,4,5,6 = 6 total

P(3 or 5) = number of  3 or 5's / total

              = 2/6

                = 1/3

Sveta_85 [38]3 years ago
5 0

Answer:

Answer:

1/36

Step-by-step explanation:

Getting a 3 is 1/6

Getting a 5 is 1/6

Multiply those and get 1/36

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Solve the equation <br> 5-(n--4)=3(n+2)
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At a certain university, 42% of the students are women and 18% of the students are engineering majors. Of the engineers, 22% are
m_a_m_a [10]

Answer:

The probability that the selected person is a woman engineering major is 0.0396.

Step-by-step explanation:

The proportion of students at the university who are women is 0.42.

<em>P (W) = 0.42</em>

The proportion of students at the university who are engineering majors is 0.18.

<em>P (E) = 0.18</em>

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<em>P (W|E) = 0.22</em>

The proportion of students at the university that are woman and engineering major is:

P (W|E)=\frac{P(W\cap E)}{P(E)} \\P(W\cap E)=P(W|E)\times P(E)\\= 0.18\times0.22\\=0.0396

Thus, the probability that the selected person is a woman engineering major is 0.0396.

7 0
3 years ago
Richard has been given an 11-question multiple-choice quiz in his history class. Each question has five answers, of which only o
Contact [7]

Answer:

Option b) 0.161                                                          

Step-by-step explanation:

We are given the following information:

We treat correct as a success.

P(Correct Answer) = \frac{1}{5} = 0.2

Then the number of questions follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 11

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P(answer at least 4 questions correctly)

P(x \geq 4)\\=1 - P(x = 0) - P(x = 1) - P(x = 2) - P(x = 3)\\=1 - \binom{11}{0}(0.2)^0(1-0.2)^{11} - ... - \binom{11}{3}(0.2)^3(1-0.2)^{8}\\=1 -0.085 -0.237-0.296 - 0.221\\= 0.161

Thus, 0.161 is the probability that Richard will answer at least 4 questions correctly.

Option b) 0.161

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What is the difference in place value between the 3 in 357 and the 3 in 734?
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The 3 in 357 means 300 while the 3 in 734 is 30 the first is a hundred place while the second is a tens
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Read 2 more answers
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