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2 years ago

Are these two claims equivalent, in conflict, or not comparable because they're talking about different things?

1 answer:

8 0

These two claims about markup and margin are <u>equivalent</u> because they discuss differently the same issue.

<h3>What are markup and margin?</h3>

A markup is a profit percent added to the cost price to determine the selling price. Thus, markup relates the percentage of profit to the cost price.

The profit margin relates the percentage of profit to the selling price.

<h3>Data and Calculations:</h3>

Selling price = 100%

Profit margin = 25%

Cost price = 75% (100% - 25%)

Markup = 33% (25%/75% x 100)

Thus, these two claims about markup and margin are <u>equivalent</u>.

Learn more about margin and markup at brainly.com/question/13248184

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PART A: complete the two-way frequency table

8_murik_8 [283]

I believe B is correct

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3 years ago

Meagan bought 6 kilograms of dried blue berries of $27.which of the following is an equivalent rate?

Trava [24]

Step-by-step explanation:

Don't see an answer but

You can divide the dollar amount by the kilograms and it should be 4.5, anything that isn't is incorrect.

for example 27/6 is 4.5

28/4 is 7 and therefore not equivalent.

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4 years ago

Hi can i calculate difficult maths question

Juli2301 [7.4K]

Answer:

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3 years ago

Meghan has two less dimes as she does nickels and one more than double the amount of quarters as she does nickels for a total of

defon

Answer:

The number of nickel = 3

Number of dime = 1

Number of quarter = 7

Step-by-step explanation:

Let us assume the number of nickels Meghan has = m

So, the number of dimes she has = m -2

And the number of quarters she has = 1 + 2 m

Now, the total amount she has = $2.00

1 nickel = $0.05 ⇒ m nickel = m ($0.05) = 0.05 m

1 dime = $0.10 ⇒ (m -2) dime = m-2 ($0.10) = 0.10 (m-2)

1 quarter = $0.25 ⇒ (1+ 2m) quarter = (1+ 2m) ($0.25) = 0.25 (1+2m)

So, according to the question:

Amount of (nickel + dime + quarter) = $2.00

⇒ 0.05 m + 0.10 (m-2) + 0.25 (1+2m) = 2

or, 0.05 m + 0.10 m - 0.20 + 0.25 + 0.5 m = 2

or, 0.65 m = 2 - 0.05

or, m = 1.95/0.65 = 3

or, m = 3

Hence, the number of nickel = 3

Number of dime = m -2 = 3-2 = 1

and Number of quarter = 2m + 1 = 7

8 0

4 years ago

If $x$, $y$, and $z$ are positive integers such that $6xyz+30xy+21xz+2yz+105x+10y+7z=812$, find $x+y+z$.

harina [27]

Answer:

Step-by-step explanation:

When we simplify we get $z(6xy+21x+2y+7)+30xy+105x+10y=812.$

Then we continue to factor to get: $(z+5)(6xy+21x+2y+7)&=847.$

We then see that we can factor $(6xy+21x+2y+7)$ into $(z+5)(3x+1)(2y+7)&=847.$

we then do the prime factorization of 847, which i think is, $7*11*11$ . we have to find the numbers that multiply to 847 and then plug them into z+5, 3x=1,2y+7.

It has to be a positive, non-negative integer, right?

We also see that 3x+1=11 so we see that x=10/3 (which wont work).

So 3x+1=7, so x=2.

So 11 has to be in another term. It has to be in 2y+7=11 so y=2

for the last term we get z+5=11 so z=6

2+2+6=10

Hope this helps and if you want please consider giving me brainliest. :)

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4 years ago