You can draw a right triangle with the informatio.
The vertical change in elevation (unknown) is the opposed leg to the angle 15°
The distance from the surveyor to the point vertically below the point on the mountain is the adjacent leg = 6 miles.
Then tan(15°) = x / 6 => x = 6tan(15) = 1.61 miles
Answer: 1.61 miles
Answer:
Yes. Both are graphing calculators. TI 83 has a black only screen while the TI 84 has a colored screen
Answer:
any line can be parallel to that as long as the y-intercepts are different and they contain the same slope which in this case, is 3.
Step-by-step explanation:
an example would be y = 3x + 4
Answer:
B.x<25
Step-by-step explanation:
Let's solve your inequality step-by-step.
3(x+3)>4(x−4)
Step 1: Simplify both sides of the inequality.
3x+9>4x−16
Step 2: Subtract 4x from both sides.
3x+9−4x>4x−16−4x
−x+9>−16
Step 3: Subtract 9 from both sides.
−x+9−9>−16−9
−x>−25
Step 4: Divide both sides by -1.
−x/
−1
>
−25/
−1
x<25
Answer:
x<25
9514 1404 393
Answer:
10
Step-by-step explanation:
Let L and T represent the initial amounts that Leo and Theo had. Let n represent the number of bills exchanged in the first exchange. Then we have ...
L -20n +50n = T -50n +20n . . . . after the first exchange, each has the same
After the second exchange, amounts trade places:
(L +30n) +6(50) = T
Substituting this into the first equation, we get ...
L +30n = ((L +30n) +300) -30n
30n = 300
n = 10
Leo gave Theo ten $20 bills.
_____
<em>Comment on the amounts</em>
Theo started with $600 more than Leo, including exactly 16 $50 bills. Leo had at least 10 $20 bills, so he could make the initial exchange. Whatever initial amount Leo had in excess of that $200 was matched in Theo's initial amount, but Theo must have had that excess in $20 bills only. For example, Leo may have started with $300 as 10×$20 +2×$50, but Theo's initial $900 would need to be 5×$20 +16×$50.
