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steposvetlana [31]

2 years ago

5

What number has 7 ones, 3 fewer thousands than ones, 5 fewer hundred thousands than ones, 2 more tens than hundred thousands, 2

more hundreds than thousands, 2 fewer ten thousands than tens, and 4 more millions than thousands?

1 answer:

Harman [31]2 years ago

5 0

Answer:

Step by step below

Step-by-step explanation:

0 000 007

0 004 007

0 204 007

0 204 047

0 204 647

0 224 647

<u>4 224 647 </u>

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Help no time plzzzz plz plz

Sav [38]

Answer:

FALSE

Step-by-step explanation:

<E in ∆AED ≅ <E in ∆CEB.

Both are 90°.

Side ED ≅ Side EB

Side AD ≅ Side CB.

Thus, two sides (ED and AD) and a non-included angle (<E) of ∆AED are congruent to corresponding two sides (EB and CB) and a non-included angle (<E) of ∆CEB. Therefore, by A-S-S Congruence Theorem, both triangles are congruent to each other not by SSS.

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3 years ago

I need the answer plssss

Artist 52 [7]

Answer: b drained the fastest I think

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

6 0

4 years ago

Help!!!! Quick and easy!

ELEN [110]

Make an equation
6p + p = 28
Combine like terms
7p = 28
Divide
p = 4

Solution: p = 4

4 0

3 years ago

4) To estimate the height of your home, you measure its shadow. The shadow of your home is 5.5 feet.

ra1l [238]

Answer:

1.375 ft

Step-by-step explanation:

10/2.5 = 4

5.5 / 4 = 1 1.5/4 = 1 3/8 = 1.375 ft

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

3 0

3 years ago