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1 year ago

Please see attached picture.

Mathematics

1 answer:

Sati [7]1 year ago

3 0

Answer:

Step-by-step explanation:

the arc length is calculated as

arc = circumference of circle × fraction of circle

= 2πr × $\frac{90}{360}$

= 2π × 16 × $\frac{1}{4}$

= 32π × $\frac{1}{4}$

= $\frac{32\pi }{4}$

= 8π ft

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A box has 16 candies.12 red and 4 yellow.If you were picking candies from the box without looking.How many candies would you hav

hodyreva [135]

Answer:

13.

Step-by-step explanation:

im not sure the smallest number but if you have 13, there is an 100% chance you got 2 of the same color

8 0

2 years ago

What’s 4/5 divided by 3

Valentin [98]

Answer:

$\frac{4}{15}$

Step-by-step explanation:

remember when dividing with fractions, you are multiplying by the reciprocal.

this means

$\frac{4}{5} \div3=\frac{4}{5}*\frac{1}{3}=\frac{4}{15}$

6 0

3 years ago

Read 2 more answers

Can someone help I have to be done by tomorrow morning plz order them from least to greatest plz

Sindrei [870]

11. 0.03, 3/10,1 1/8,1 5/6,2

7 0

3 years ago

14.What is the solution of the system?

Archy [21]

Answer:

14. x=-2.5, y = -7

15. x=28 y = -20

Step-by-step explanation:

14. Let's solve this system by elimination. Multiply the first equation by -1.

-1*(4x-y)= -1*(- 3)

-4x +y = 3

Then add this to the second equation.

-4x+y = 3

6x-y= - 8

--------------

2x = -5

Divide each side by 2

x = -2.5

We still need to find y

-4x+y =3

-4(-2.5) + y =3

10 +y =3

Subtract 10 from each side.

y = 3-10

y = -7

15.I will again use elimination to solve this system, because using substitution will give me fractions which are harder to work with. I will elimiate the y variable. Multiply the first equation by 11

11( 5x+6y)= 11*20

55x+66y = 220

Multiply the second equation by -6

-6(9x+11y)=32*(-6)

-54x-66y = -192

Add the modified equations together.

55x+66y = 220

-54x-66y = -192

---------------------------

x = 28

We still need to solve for y

5x+6y = 20

5*28 + 6y =20

140 + 6y = 20

Subtract 140 from each side

6y = -120

Divide by 6

y = -20

3 0

2 years ago

A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
<em>Then for the x direction</em> it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
In the same fashion, <em>for the y direction</em>, the initial velocity is $v_{0y} =$ 0 m/s, the acceleration in y direction is $a_{y}$ 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: $v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}$

8 0

3 years ago