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Digiron [165]
3 years ago
13

What is the product of (x+1) and (2x^2+3x-1)

Mathematics
2 answers:
ELEN [110]3 years ago
6 0

(x + 1)(2x^2 + 3x - 1) : Can be solved in multiple ways but easiest for me :P

x (2x^2 + 3x - 1) + 1(2x^2 + 3x - 1)

(2x^3 + 3x^2 - x) + (2x^2 + 3x - 1)

2x^3 + 5x^2 + 2x - 1

Sedbober [7]3 years ago
4 0

Answer:

Product is 2x³ + 5x² + 2x - 1.

Step-by-step explanation:

Given :  (x+1) and (2x²+3x-1).

To find : what is the product .

Solution : We have given that

(x+1) and (2x²+3x-1).

Product : (x+1)(2x²+3x-1).

Now, distribute x+ 1 over 2x²+3x-1.

x ( 2x²+3x-1) + 1( 2x²+3x-1).

2x³ + 3x² - x + 2x²+3x-1.

Combine like terms

2x³ + 2x²+3x² - x +3x-1.

2x³ + 5x² + 2x - 1.

Therefore, Product is 2x³ + 5x² + 2x - 1.

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Answer:

0.034921 miles or 1843774 feet tall

Step-by-step explanation:

Using trigonometric functions we know that x=rcos(\theta) and y=rsin(\theta) where \theta=angle and r is the hypotenuse of the triangle.

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Now we will calculate the height of the building using the y equation and so:

y=rsin(\theta)\\\\y=\frac{1}{cos(2)} \times sin(2) = \frac{sin(2)}{cos(2)}=tan(2)=0.034921mi

The building is 0.034921 miles or approximately 184.3774 feet tall.

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