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SVETLANKA909090 [29]
2 years ago
11

social media data may be considered a form of secondary data, since it is information that does not originate as a result of a m

arketing research project.
Business
1 answer:
svet-max [94.6K]2 years ago
7 0

social media data may be considered a form of secondary data.

<h3>Why can we consider social media data a form of secondary data?</h3>

There are many different categories of data that may be used in data analytics. For instance, the contrast between qualitative and quantitative data is frequently used. You might also separate your data depending on aspects like sensitivity.

For instance, is it widely known or is it really private?

The source of the data is perhaps the most basic distinction between various forms of data. Are they, specifically, first-party, second-party, or third-party data? These essential data sources all contribute in some manner to the data analytics procedure.

To learn more about secondary data from given link

brainly.com/question/18118203

#SPJ4

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According to COSO, a system of internal controls is designed to provide reasonable assurance about the achievement of entity obj
kondor19780726 [428]

Answer:

The correct answer is: b, c and d.

Explanation:

Internal controls are are policies or processes put in place by the management arm of a company to ensure that the goals set by the firm are achieved both in the long term and short-term. These processes ensure safe custody of assets, reliability in financial information provided or used by the firm, compliance with regulations as well as  effectiveness and efficiency in the day to day operations. With this in mind, maximisation of management compensation is not a goal of internal controls. According to COSO, there are 3 main goals of internal controls: to ensure effectiveness and efficiency of operations, reliability of financial reporting and compliance with laws and regulations.

4 0
3 years ago
Sandhill Company is constructing a building. Construction began on February 1 and was completed on December 31. Expenditures wer
Alla [95]

Answer:

$2,319,000

Explanation:

Amount

March1 $1,884,000

June 1 $1,284,000

Dec 31 $3,082,450

Capitalization period

March1

10/12×$1,884,000 =$1,570,000

June 1

7/12 $1,284,000=$749,000

Dec 31

0

Weighted Average Accumulated expenditure

March 1 $1,570,000

June1 $749,000

Dec 31 $0

Total $2,319,000

8 0
3 years ago
Powerpoint slides can be quite effective and used best when they
Artyom0805 [142]
<span>The correct statement on Powerpoint slides, which is a presentation of a series of still images on a projection screen or electronic display device, is that: Powerpoint slides can be quite effective and used best when they are used properly as an enhancement to the speaker's presentation.</span>
8 0
3 years ago
Granite State Airlines serves the route between New York and Portsmouth, NH, with a single-flight-daily 100-seat aircraft. The o
TEA [102]

Answer:

Given data: One flight with total seats = 100

Full fare passengers, cost per ticket=$150, mean=56 passengers, SD=23

Discount fare passengers, cost per ticket=$100, mean=88 passengers, SD=44

(a) Here, though there is a hint to use the CDF, since the confidence interval is not given we will make some simplying assumptions that will reduce the complexity of the question, of course keeping the question statistically correct.

this question wants us to maximize total revenue per flight (one way), we can do that by taking only full fare passengers or total revenue will be 150*100=$15,000, but since historical probability shows a mean of 56 with a standard deviation of 23, we can assume in best case scenario total full fare ticket passengers will be 56+23=79, leaving 21 tickets for discount passenger, in this case the total revenues will be 79*150+21*100=$13,950

(b) Now, the new constrained policy is giving a clear cut number of seats to each category of pasengers, 44 for discount (total revenues 44*100) and 56 for full fare (total revenues 56*150) both of which are within the probabilities given earlier (full fare mean=56, discount mean=88). Total revenues in case will be 44*100+56*150=$12,800.

(c) Gain is the difference of the excess revenues in both cases of optimal total revenues and limited seats policy or answer (a) - answer (b) = $13,950- $12,800=$1,150

(d) Realistically speaking, there is no answer for this question without a clear cut confidence interval. Another simplifying assumption we can make here is taking the mean passengers as expected bookings (can be tweaked once confidence interval or degree of significance is given). so total revenues in this case will be 44*100 from discount and 56*150 from full fare passengers. That is still similar to answer (c) due to our assumption/lack of constraints, so our optimal booking will be 54 full fare tickets and 44 discount passenger tickets. You can also take worst case scenario by subtracting SD of each passenger type from the mean or go the best case scenario in which SD of full fare will be added to the mean while the pending seats (left over from 100) will be the total to discount fare for optimal revenue collection.

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4 years ago
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