1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dimulka [17.4K]
2 years ago
11

A new company, Games 2 U, is selling unlimited video game rentals online for up to 5 devices. They are offering two different pr

icing options. The EZ Plan is $0.10 per minute. The Big Time Gamer Plan is $0.05 per minute plus a $100 monthly charge.
Let x be minutes playing games in a month and write 2 expressions to represent each pricing plan. Set them equal to each other. DO NOT SOLVE equation until item 12.
Mathematics
1 answer:
Basile [38]2 years ago
8 0

The expression of the two plans( EZ Plan and Big Time Gamer Plan) are as follows:

y = 0.10x

y = 0.05x + 100

<h3>How to represent expression?</h3>

The company is offering two different pricing options.

The EZ Plan is $0.10 per minute.

The Big Time Gamer Plan is $0.05 per minute plus a $100 monthly charge.

Therefore, the EZ pricing plan can be express as follows:

y = 0.10x

Therefore, the Big Time Gamer Plan can be express as follows:

y = 0.05x + 100

where

x = minutes playing games in a month

y = The total cost of the plans

Let's set them equal to each other.

0.10x  = 0.05x + 100

Learn more about expression here: brainly.com/question/17207480

#SPJ1

You might be interested in
Determine if the lines are parallel, perpendicular or neither y=-3/2x-4 and y=2/3x-7
aliya0001 [1]

Answer:

<u>They are perpendicular</u>

Step-by-step explanation:

Perpendicular lines have slopes that are negated versions of the other or positive versions of the slope of the other. The slopes are also flipped.

Parallel lines have the same slope.

Neither is when the lines do not follow either of these definitions.

The slope of your two lines are -3/2 and 2/3. These slopes are flipped and the opposite negations of each other. <u>This means the lines are perpendicular.</u>

<u />

4 0
3 years ago
What is the value of 0 in 302
vlada-n [284]
The answer is 10 because its in the tens place
4 0
3 years ago
Part A: Find the GCF of 56 and 96. It is 8, already did this
enot [183]

Question: Part A: Find the GCF of 56 and 96. It is 8, already did this

Part B: Using the GCF you found in Part A, rewrite 56 + 96 as two factors. One factor is the GCF and the other is the sum of two numbers that do not have a common factor. Show your work.

Answer & explanation: Quick-Start Guide. When you enter an expression into the calculator, the calculator will simplify the expression by expanding multiplication and combining like terms. This website will help you out, I think! https://wpblog.wyzant.com lessons Expression Factoring Calculator – Wyzant Lessons

3 0
3 years ago
Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"
vampirchik [111]
\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h

Employ a standard trick used in proving the chain rule:

\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h

The limit of a product is the product of limits, i.e. we can write

\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)

The rightmost limit is an exercise in differentiating \sqrt x using the definition, which you probably already know is \dfrac1{2\sqrt x}.

For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}

which in turn is the derivative of \tan y, another limit you probably already know how to compute. We'd end up with \sec^2y, or \sec^2\sqrt x.

So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
7 0
3 years ago
A student receives test scores of 62, 83, and 91. This student's term project score is 88. Each test is worth 20% of the final g
miskamm [114]

Answer:

The student's current average score will be 69.2

Step-by-step explanation:

Let first test be TEST A: which is 20 of total and secures 62

Let second test be TEST B: which is 20 of the total marks and has secured 83.

Let third test be TEST C: which is 20 of total and has secured 91.

And now the TEST D which is 25 of total and has secured 88.

Therefore, by multipying across

{0.2}\times{62} = 12.4

{0.2}\times{83} = 16.6

{0.2}\times{91} = 18.2

{0.25}\times{88} =22

Now, by adding the scores to get the average score

We get, 69.2.

6 0
3 years ago
Other questions:
  • A spinner has three sections. The table shows the results of spinning 80 times. ({Section 1|18}{Section 2|30}{Section 3|32}) Wha
    9·1 answer
  • Airplanes are sometimes used to fight fires . A certain airplane can deliver 3.9 * 10^4 liters of water in one trip . How much w
    12·1 answer
  • Factor the sum of terms as a product of the gcf and sum. 60 + 72
    11·1 answer
  • Boris is taking a quiz for an online class. For the quiz, the system randomly assigns 2 high-difficulty questions, 7 moderate-di
    10·1 answer
  • (6×5)×_=300 complete the pattern
    6·1 answer
  • In the graphic above, ΔRED ≅ ΔTAN by: aHL. bSSA. cSAS. dThe triangles are not congruent.
    5·1 answer
  • Please help hurry!!!!!!!
    9·1 answer
  • Solve for the missing variable(s) and SHOW ALL WORK
    6·1 answer
  • HELP PLEASE ASAP I WILL MARK BRAINLIEST
    13·1 answer
  • Alison had lost some puzzle pieces. She found 3/10 of them under the coffee table and another 4/10 of them under the couch. How
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!