9514 1404 393
Answer:
- width 117 feet
- length 292 feet
Step-by-step explanation:
Let w represent the width of the field. Then w+175 is its length. The perimeter is ...
P = 2(L+W)
818 = 2((w+175) +w) . . . . . fill in given values
818 = 4w +350 . . . . . . . . . simplify
468 = 4w . . . . . . . . . subtract 350
117 = w . . . . . . . . divide by 4
w+175 = 292 . . . . find the corresponding length
The width of the field is 117 feet; the length is 292 feet.
Degree is the value of the highest power of the variable, and hence in this case is 8
Given=
length of the segment AD is 28 cm
distance between the midpoints of segments AB and CD is 16 cm
find out length of BC
To proof
AD = 28 cm
let the midpoint of the AB is E.
let the midpoint of the CD is F.
E & F are the midpoints i.e these points divide AB & CD in two equal parts.
Let BC = z
Let AE = EB = x ( E is midpoint)
Let CF = FD = y (F is midpoint)
the equation becomes
2x + 2y + z = 28
x + y + z = 16
mulitipy above equation by 2
we get
2x + 2y + 2z = 32
thus solving the equations
2x + 2y + 2z = 32
2x + 2y + z = 28
we get
z = 4 cm
i.e BC = 4 cm
Hence proved
Answer:
52.9%
Step-by-step explanation: