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Ainat [17]
2 years ago
13

In figure 2, find x if the perimeter is 4. Does each answer make sense? Why or why not?

Mathematics
1 answer:
stealth61 [152]2 years ago
8 0

The value of x is equal to 1.5.

It is required to find x.

<h3>What is quadratic equation?</h3>

Any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power. The quadratic formula to solve a quadratic equation ax2 + bx + c = 0 is x = [-b ± √(b2 - 4ac)]/2a.

Given that:

So for the triangle, the perimeter would be:

(x^{2} +x+3)+(x^{2} +2x-2)+(x^{2} +2x-9)=4

By solving in above equation, we get

(x^{2} +x+3)+(x^{2} +2x-2)+(x^{2} +2x-9)=4\\\\\\\2x^{2}+5x-8=4\\\\2x^{2}+5x-12=0\\\\2(x + 4)(x - 1.5)=0\\\\ x=-4\\\\ x=1.5

So, we take x= 1.5 and neglect -4 because we can't take negative roots of the quadratic equation.

Hence, the value of x is equal to 1.5.

Learn more about quadratic equation here:

brainly.com/question/17177510

#SPJ1

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What is the slope of this line? <br> A.) −1/2<br> B.) 1/2<br> C.) 2<br> D.) I don't know.
gregori [183]

Answer:

2

Step-by-step explanation:

8 0
3 years ago
Each side of a square is increasing at a rate of 5 cm/s. At what rate is the area of the square increasing when the area of the
icang [17]

Answer:

<h2>70cm/s</h2>

Step-by-step explanation:

Area of a square with side of length L is expressed as A = L². The rate at which the area is increasing will be expressed as dA/dt.

dA/dt = dA/dL * dL/dt where

dL/dt is the rate at which each side of the square is increasing.

Since dA/dL = 2L, dA/dt = 2L dL/dt

Given dL/dt = 5cm/s and the Area of the square = 49 cm²

49 = L²

L = √49

L = 7cm

dA/dt = 2(7) * 5

dA/dt = 14*5

dA/dt = 70cm/s

The rate at which the area of the square is increasing is 70cm/s

3 0
3 years ago
Can someone please help me on this?
shepuryov [24]

Answer:

For every one hour, there is 25 of the other side, so 1:25?

Step-by-step explanation:

8 0
3 years ago
Whats 9 + 10. im really confused please dont say 21
Anna71 [15]

Step-by-step explanation:

  • 9+10=19

<h3>hope it helps.</h3><h3>stay safe healthy and happy.</h3>
3 0
3 years ago
Read 2 more answers
Give the number to which the Fourier series converges at a point of discontinuity of f.
quester [9]

Answer:

The Fourier series of f(x) converges to 3 at the points x= π+2kπ, where k is an integer.

Step-by-step explanation:

First, recall that the function f(x) is extended 2π periodic to the whole real line, in order to obtain a valid Fourier expansion. Remember that a Fourier series is formed by a sines and cosines, which are 2π-periodic.

So, the 2π-periodic expansion of f(x) is discontinuous at the points π+2kπ, in particular π and -π. Check the attached figure to a better understanding.

Now, the Dirichlet theorem on the convergence of a Fourier series tells us that the series converges to the function at the points of continuity, and at points of discontinuity the sum of the series is

\frac{f(x_0+)+f(x_0-)}{2}.

Here we understand the notation f(x+) and f(x-) as

f(x_0+) = \lim_{x\rightarrow x_0}f(x), x>x_0

and

f(x_0-) = \lim_{x\rightarrow x_0}f(x), x.

In this particular case

f(\pi-) = \lim_{x\rightarrow \pi}(3-2x) = 3-2\pi, x.

For the limit f(\pi+) = \lim_{x\rightarrow \pi}(3-2x), with x>\pi recall that our function is 2π-periodic, so the values of f near π, with x>π are the same when x is near -π and x>-π. Again, check the attached figure. So,

f(\pi+) = \lim_{x\rightarrow \pi}(3-2x) = 3+2\pi, x.

Thus,

\frac{f(\pi+)+f(\pi-)}{2} = \frac{3+2\pi +3-2\pi}{2} = \frac{6}{2} =3.

Note: In the attached figure we only have drawn three repetitions of the 2π-periodic extension of f, recall that the extension is <em>ad infinitum</em>. Also, the points drawn in the dotted lines are the sum of the series at the points of discontinuity.

6 0
3 years ago
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