100-35 = 65
65% de 2300 = 1495 (mes 1)
2300-1495 = 805 (mes 2)
65% de 805 = 523,25 (mes 3)
65% de 523,25 = 340,1125 ~ 340,10 (mes 4)
Answer:
i think it is 1% sry if wrong
Step-by-step explanation:
Well to find this answer, I assume that you want me to help with finding the area. Let's start with the area of the stage. Off of the info you gave me, I assume that the stage and pit are rectangles. So to find the area of the rectangles, we need to use the area formula A=l×w. Plug in the numbers into the formula and we get A=10×5. So the area of the stage is 50 yards. Now do the same thing for the pit, and we get A=4×2. So the pit's area is 8 yards. Add 50 and 8 to get the total area and we get 58. So the stage and the orchestra pit take up 58 yards of floor space. Hope I helped!
Answer:
KL = 50
Step-by-step explanation:
∆JML is similar to ∆JNL. it follows that:
[tex] \frac{JM}{JN} = \frac{JL}{JK} [\tex]
JM = 4 + 20 = 24
JN = 4
JL = 10 + KL
JK = 10
Plug in the values
[tex] \frac{24}{4} = \frac{10 + KL}{10} [\tex]
[tex] 6 = \frac{10 + KL}{10} [\tex]
Multiply both sides by 10
[tex] 6*10 = \frac{10 + KL}{10}*10 [\tex]
[tex] 60 = 10 + KL [\tex]
Subtract 10 from each side
[tex] 60 - 10 = KL [\tex]
[tex] 50 = KL [\tex]
KL = 50