I NEED HELPP ASAP!!!

Claire has $210 to spend on clothes. She wants to buy a pair of shorts and some shirts. The cost of a pair of shorts is $25, and

Komok [63]

Answer:

discount of 50% on one shirt, which inequality can be used to find the maximum number of shirts, n, that she can buy?

Step-by-step explanation:

has $210 to spend on clothes. She wants to buy a pair of shorts and some shirts. The cost of a pair of shorts is $25, and the cost of a shirt is $40. If she gets a discount of 50% on one shirt, which inequality can be used to find the maximum number of shirts, n, that she can buy?

3 0

4 years ago

A journalist reported that the average amount of time that a French person spends eating lunch at a restaurant is 22 minutes. Pe

maw [93]

Answer:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

$t=\frac{19 -22)-(0)}{4.095\sqrt{\frac{1}{8}+\frac{1}{7}}}=-1.416$

Step-by-step explanation:

Data given

American: 21,17,17,20,25,16,20,16 (Sample 1)

French: 24,18,20,28,18,29,17 (Sample 2)

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

This last one is an unbiased estimator of the common variance $\sigma^2$

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2 \neq 0$

Our notation on this case :

$n_1 =8$ represent the sample size for group 1

$n_2 =7$ represent the sample size for group 2

$\bar X_1 =19$ represent the sample mean for the group 1

$\bar X_2 =22$ represent the sample mean for the group 2

$s_1=3.117$ represent the sample standard deviation for group 1

$s_2=5.0$ represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

$S^2_p =\frac{(8-1)(3.117)^2 +(7 -1)(5.0)^2}{8 +7 -2}=16.770$

And the deviation would be just the square root of the variance:

$S_p=4.095$

And now we can calculate the statistic:

$t=\frac{19 -22)-(0)}{4.095\sqrt{\frac{1}{8}+\frac{1}{7}}}=-1.416$

Now we can calculate the degrees of freedom given by:

$df=8+7-2=13$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{13}$

So with the p value obtained and using the significance level assumed $\alpha=0.1$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 10% of significance we don't have significant differences between the two means.

3 0

3 years ago

The person is a member for super for a female boss over in the and loss increased approximately linearly from 5% in 1974 to 9% i

natali 33 [55]

Answer:

1998

y=6x+1944

Step-by-step explanation:

The percentage of Male workers who prefer a female boss over a male boss increased approximately linearly from 5% in 1974 to 9% in 1998. Predict when 9% of male workers will prefer a female boss

it is explicit from the question that 9% of male workers prefer female boss in 1998. but we can predict a model for this by getting the slope of the graph

y=the year

x=the percentage of men who prefer a female boss

s=y2-y1/(x2-x1)

s=1998-1974/(9-5)

s=24/4

s=6

therefore we have

y=mx+c

y=6x+c........1

when y=1998,x=9

1998=6(9)+c

c=1944

from equation 1

y=6x+1944

8 0

4 years ago

Instructions: Write the explicit rule. Remember to simplify and do not put spaces in your answer. Sequence: 30,0,−30,−60,… 30 ,

kodGreya [7K]

Answer:

a(n)=60-30n

Step-by-step explanation:

Equation to use:

a(n) = a(1) + d(n-1)

where a(1) is the first term, d is the common difference between terms, and n is the nth term you are trying to find.

In this case, a(1) is 30, d is -30, and n is just n.

If you plug that into the equation and use the distributive property, you would get: a(n) = 30 -30n + 30.

Adding the two 30's gets you: a(n) = 60 - 30n, which is the solution.

7 0

4 years ago

You travel 150 miles on 5 gallons how far did you travel per gallon?

Artyom0805 [142]

Answer:

Step-by-step explanation:

6 0

3 years ago

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