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andriy [413]
1 year ago
7

The most common triathlon distance for bicycle route is 40 kilometers.

Mathematics
1 answer:
deff fn [24]1 year ago
3 0

The cycle route  for the triathlon is of 26 miles

A triathlon is an athletic event which involves races which involves of swimming, cycling, and running over various distances

According to the given data,

The most common triathlon distance for Bicycle route is 40 kilometers

1 mile = 1 .6 kilometer

Now we know that 1.6 kilometer is 1 mile

So we are required to convert kilometers of triathlon race into  miles

Therefore, 40 kilometers in mile will be= 40/1.6 = 25 miles

Hence the cycle route is of 26 miles .

For further reference on conversion of miles to kilometer:

brainly.com/question/20857946?referrer=searchResults

#SPJ9

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What is the least common multiple you could use to find 4/5 + 5/6
scoray [572]

Answer: 30

Step-by-step explanation: 30 is the first multiple that both 5 and 6 share, and as such should be the denominator

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In triangle , side and the perpendicular bisector of meet in point , and bisects . If and , what is the area of triangle
stich3 [128]

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, 145–√5  is the area of a triangle.

I supposed here that [ABD] is the perimeter of ▲ ABD.

As  BD  is a bisector of  ∠ABC ,

ABBC=ADDC=97

Let  ∠B=2α

Then in isosceles  △DBC

∠C=α

BC=2∗DC∗cosα=14cosα

Thus  AB=18cosα

The Sum of angles in  △ABC  is  π  so

∠A=π−3α

Let's look at  AC=AD+DC=16 :

AC=BCcosC+ABcosA

16=14cos2α+18cosαcos(π−3α)

[1]8=7cos2α−9cosαcos(3α)

cos(3α)=cos(α+2α)=cosαcos(2α)−sinαsin(2α)=cosα(2cos2α−1)−2cosαsin2α=cosα(4cos2α−3)

With  [1]

8=cos2α(7−9(4cos2α−3))

18cos4−17cos2α+4=0

cos2α={12,49}

First root lead to  α=π4  and  ∠BDC=π−∠DBC−∠C=π−2α=π2 . In such case  ∠A=π−∠ABD−∠ADB=π4, and  △ABD  is isosceles with  AD=BD. As  △DBC  is also isosceles with  BD=DC=7,  AD=7≠9.

Thus first root  cos2α=12  cannot be chosen and we have to stick with the second root  cos2α=49. This gives  cosα=23  and  sinα=5√3.

The area of a triangle ABD=12h∗AD  where h  is the distance from  B  to  AC.

h=BCsinC=14cosαsinα

Area of  triangle ABD=145–√5

= 145–√5.

Incomplete question please read below for the proper question.

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, what is the area of triangle ABD?

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6 0
2 years ago
Divide 169 mi in the ratio 5 : 8.
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Answer:

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