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uysha [10]
3 years ago
13

What is 354605 rounded to the nearest thousand

Mathematics
2 answers:
galben [10]3 years ago
7 0
The answer is 355,000
tatuchka [14]3 years ago
3 0
It would be 355,000
Hope this helps!
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1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0
3 years ago
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Answer:

1) 250 meters= 0.25 km

2) 12 meters=  0.012km

3) 1 meter= 0.001 km

The constant of proportionality is 1000 meters in 1km (1000 meters)

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4 0
3 years ago
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AnnZ [28]
\frac{3}{5} :11=  \frac{3}{5} : \frac{11}{1} = \frac{3}{5} * \frac{1}{11} = \frac{3}{55}
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3 years ago
Is Triangle B a rotation of Triangle A? Explain how you know.
Natasha_Volkova [10]

Answer:

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Step-by-step explanation:

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Given g (2) = -2x + 5 - 1.
Verizon [17]

Answer:

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