Write the whole number in numerical form.seven hundred forty-three million,five hundred fifty-four

sammy [17]

Answer:

Explanation:

7. f(x) = x^4 + 3x^3 - 6x^2 - 10x + 8
f(2) = 2^4 + 2^3 - 6^2 - 10(2) + 8
f(2) = 16 + 8 - 12 - 20 + 8
f(2) = 0

8. x^2 - 9 = (x - 3)(x + 3)
x ^2 + x - 6 = (x + 3)(x -2)

Thus, the common factor is x + 3

5 0

1 year ago

PLZ HELP AND EXPLAIN !! Arron borrowed $200 from his cousin. He promised to repay the loan in 2 years at a simple annual interes

Dmitriy789 [7]

The first thing you have to do is know the equation. The equation is a(1+p)^t.
a= the amount of money p= the percent represented as a decimal and t=time ( the t is raised as an exponent)
so, in this case, it is represented as 200(1+0.05)^2\
200(1.05)^2
200(1.1025)
220.5 That is how much extra he would owe in interest fee's

5 0

2 years ago

Find value of x such that the data set has a mean of 105: 99, 119, 106, 112; 108

Marizza181 [45]

I'm assuming that x is part of the data set, and, with x, the mean equals 105. To find the value of x, you must add all the data values together to get 544+x (you still don't know what x equals). Then put 544+x over how many days values there are, including x (there are 6). You should have 544+x/6. Now, as this is how you would calculate the mean if you knew what x was equal to, you must set it equal to the mean, since you know what it is (105). You should now have 544+x/6 = 105. You have your equation set up--now you just have to solve it. I would multiply by 6 on both sides to get rid of the 6 on the left side. You would then have 544+x = 630. I would finally subtract 544 from both sides to get x = 86. Your final answer is x = 86.

6 0

2 years ago

Branden and Pete both play running back. Branden carries the ball 75 times for 550 yards and Pete had 42 carries for 380 yards w

mars1129 [50]

Answer:

Pete runs farther per carry.

Step-by-step explanation:

Given:

Branden and Pete both play running back.

Branden carries the ball 75 times for 550 yards.

Pete had 42 carries for 380 yards

Question asked:

Who runs farther per carry ?

Solution:

First of all we find each boy's distance covered per carry:-

<u>For Branden</u>

Branden carries the ball 75 times for = 550 yards.

Branden carries the ball 1 time for = $\frac{550}{75} =7.34\ yard$

Pete carries 42 times for = 380 yards

Pete carries 1 time for = $\frac{380}{42} =9.05\ yards$

As Pete runs 9.05 yards for 1 carry while Branden runs 7.34 yards for 1 carry, hence Pete runs farther per carry.

3 0

2 years ago

The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista

baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{10.634 - \mu}{\sigma}$