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Alla [95]
2 years ago
9

Can you guys help me find the domain? (finding the domain graphically)

Mathematics
1 answer:
malfutka [58]2 years ago
3 0

Answer:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

Step-by-step explanation:

Hope this helps i would give answer but i dont know what the answer is so sorry but hope this helps you.

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Please help I'm almost done with this course I just need a few more answered
iogann1982 [59]

The answer would be B.

Hope this helped :)

6 0
2 years ago
What are the apparent zeros of the cubic function graphed above? (also if you have the answers to the rest of this test plz send
Mazyrski [523]

<em>The point where a function (for our problem its the cubic function shown)</em>

  • cuts/crosses the x-axis

<u>and/or</u>

  • touches the x-axis

<em>is a zero of the function.</em>

From the graph shown, we can clearly see that it cuts the x-axis at -1 and touches the x-axis at 2.

So the zeros are at -1 and 2.


ANSWER: {-1,2}


7 0
3 years ago
Read 2 more answers
The picture below shows a right-triangle-shaped charging stand for a gaming system:
Kobotan [32]

Answer:

The answer is between first option and last option.

Step-by-step explanation:

That my Contributions to this questions

8 0
2 years ago
I need help with number 1 please
Bond [772]
306 / 3.6 = 85 gallons per minute

5,200 = 85x
x = <span>61.1764705882

hope this helps</span>
4 0
2 years ago
Read 2 more answers
Could u guys try this one out as well
Korolek [52]

Answer:

D) a reflection over the line x = 0 followed by a reflection over the line y = 0.

Step-by-step explanation:

In this problem, the original figure is in quadrant I (1) and the second image is in quadrant III (3).  In order for the figure to make this transition and be 'flipped' into the opposite direction of the original figure, a reflection would have to take place.  If triangle 'A' is reflected over the line y = x or y = -x, the orientation of the triangle would stay the same, meaning the point of the triangle would still face upward.  If you reflect over the line x = 0 and then again over the line x = 0 (as in C), your triangle would be in the same spot.  However, if you reflect triangle 'A' over x = 0, you would get a 'flipped image' into quadrant 4 and the orientation of the triangle would face downward.  Following this reflection by another reflection over the line y=0 would give you the mirror image in quadrant III (3).  So, D is the correct sequence of reflections.  

3 0
3 years ago
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