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dem82 [27]
3 years ago
7

The rectangular sandbox at the local community park has a width of 24.5 meters and its length is 31.7 meters. What is the perime

ter, in meters, of the rectangular sandbox?
Mathematics
1 answer:
eduard3 years ago
5 0
The answer is 112.4 because 24.5+24.5+31.7+31.7=112.4.
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Half of j minus 5 is the sum of k and 13
hoa [83]
\dfrac{1}{2}j-5=k+13
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3 years ago
Plz help quick need for school rn
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Answer: 1/8

Step-by-step explanation: (:

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Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2
drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is x^{3}-2 x^{2}-x+2=0

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is  

F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0

\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}

So, the equation is x^{3}-2 x^{2}-x+2=0

Let us put x = 0 in f(x) to check whether our answer is correct or not.

\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2

Hence, the equation of the polynomial is x^{3}-2 x^{2}-x+2=0

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Answer:

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Step-by-step explanation:

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JulijaS [17]
There are 7 people who play brass
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3 years ago
Read 2 more answers
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