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2 years ago

How are the perimeters of the preimage polygon and the image polygon related? Explain.

Mathematics

1 answer:

Romashka-Z-Leto [24]2 years ago

7 0

The difference between Pre-Image and Image is given as follows:

Image is the shape AFTER a transformation is the picture of the transformation.
A transformation's preimage is the shape BEFORE the change.

<h3>How do you define relationships between Image and Preimage?</h3>

Usually, the difference between image and pre-image is the way or method of transformation.

<h3>What is transformation in math?</h3>

A transformation is a broad phrase covering four distinct methods of changing the shape and/or location of a point, line, or geometric figure.

The Pre-Image is the original shape of the item, and the Image during the transformation is the final shape and location of the object.

The types of transformation in math are;

translation
rotation
reflection, and
dilation.

Learn more about pre-image:
brainly.com/question/8405245
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Read 2 more answers

Please help me answer this worksheet (Geometry Worksheet 3.3)

AysviL [449]

As per the reference document attached thereby along with the question statement, if (∠SOX = 160°), [∠1 = (x + 14)], and [∠2 = (3x – 10)], then the measure of ∠2 in degrees will be 113°

As per the reference document attached thereby along with the question statement, (∠SOX = 160°), and it's constituent angles

[∠1 = ∠SOW = (x + 14)], and [∠2 = ∠WOX = (3x – 10)],

And we are required to determine the measure of ∠2.

Since, [(∠SOW + ∠WOX) = ∠SOX],

Therefore, [{(x + 14) + (3x – 10)} = 160°]

Or, [{(x + 3x) + (14 - 10)} = 160°]

Or, [(4x - 4) = 160°]

Or, [4x = (160 + 4)°]

Or, (4x = 164°)

Or, [x = (164/4)°]

Or, (x = 41°)

Or, [(3x – 10) = {(3 * 41) - 10}°]

Or, [∠2 = (123 - 10)°]

Or, (∠2 = 113°)

That is, if (∠SOX = 160°), and it's constituent angles (∠1) and (∠2) measure as [∠1 = ∠SOW = (x + 14)], and [∠2 = ∠WOX = (3x – 10)], then the measure of ∠2 in degrees will be 113°

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