Answer:
l think so because -3 if you add a 0 (-30) its smaller than -33
Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
Answer:
4/5/6= 6/4/5
Step-by-step explanation:
because that i have like with the mose cocative invous
Answer:
nothing is there
Step-by-step explanation:
