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Debora [2.8K]
3 years ago
11

What are the x- and y- coordinates of point P on the directed line segment from A to B such that P is the length of the line seg

ment from A to B?
(2, –1)
(4, –3)
(–1, 2)
(3, –2)
Mathematics
1 answer:
erica [24]3 years ago
4 0

Answer:

the correct answer is (-1, 2)

Step-by-step explanation:


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Divide 3 by 8, then multiply z by the result
Sonbull [250]

3÷ 8 ·z

3/8 ·z

3/8z

I think i'm just supposed to simplifiy it??

8 0
2 years ago
Two ships leave from the same port. One travels west 84 miles and the other travels 62 miles north. Determine the distance betwe
Lerok [7]
The distance the ships traveled are like the legs of a triangle and the question wants to know the hypotenuse. To find the hypotenuse, use the pythagorean theorem. this is a^2 + b^2 = c^2, with a and b being the legs and c being the <span>hypotenuse.
</span>Plug in known values:
84^2 + 62^2 = c^2
Solve:
84^2 = 7056
62^2 = 3844
7056 + 3844 = c^2
7056 + 3844 = 10900
10900 = c^2
Now you just need to isolate c by finding the square root of both sides.
√10900 = 104.403
√c^2 = c

So c = 104.403, or just 104.40 when rounded to the nearest tenth.
And if c is 104.40, then that means the hypotenuse is 104.40.
And all of that basically means that the distance between the ships is 104.40 miles.
5 0
3 years ago
I need help on doing this
Rudik [331]

Answer:

#5A=6

5B=4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
I need to increase my sales by 35% this month I’m currently at 45 sales how many sales do I need to meet my goal ?
telo118 [61]
Assume that 100% = 45 sales and 35% = X sales amount

You can create a ratio to help you solve for x

45 = 100%
x   =  35 %

Which is equal to this fraction:  (45/x) = (100/35)

Solving for X by cross multiplying and dividing by 100:
  [(45)(35)] / 100  =  X = 15.75 = 16 sales (rounded up)

You would need at least 16 sales to increase sales total by 35%
8 0
3 years ago
Read 2 more answers
Pleasee help ASAP!! No links pleaseee!!!
Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(2-0)^2+(4-1)^2}

AB=\sqrt{(2)^2+(3)^2}

AB=\sqrt{4+9}

AB=\sqrt{13}

Similarly,

BC=\sqrt{(6-2)^2+(0-4)^2}

BC=\sqrt{(4)^2+(-4)^2}

BC=\sqrt{16+16}

BC=\sqrt{32}

BC=4\sqrt{2}

Now, the length of the rectangle is AB=\sqrt{13} and the width of the rectangle is BC=4\sqrt{2}. So, the area of the rectangle is:

A=length \times width

A=\sqrt{13}\times 4\sqrt{2}

A=4\sqrt{26}

A\approx 20

Therefore, the area of the rectangle is 20 square units.

3 0
2 years ago
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