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Marta_Voda [28]
2 years ago
10

An item is regularly priced at $97. Lucy bought it at a discount of 55% off the regular price.

Mathematics
1 answer:
Anastasy [175]2 years ago
5 0
43.65 and saved 53.35
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What is the Converse of the Pythagorean Theorem? The theorem states that if the square of the length of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle
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Two expressions are shown below. Explain whether or not expressions P and Q are equivalent
bulgar [2K]

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I don't see any expressions shown below.

Step-by-step explanation:

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3 years ago
Change the expression to a single square root, or its opposite:
aleksley [76]

Answer:

a)2\sqrt{2}=\sqrt{8}

b)-7\sqrt{3} =-\sqrt{147}

c)\frac{1}{3} \sqrt{18b}  =\sqrt{2.b}

d)5\sqrt{y} =\sqrt{25y}

e)-6\sqrt{2a}  =-\sqrt{72a}

f)-0.1\sqrt{200c}=-  \sqrt{2c

Step-by-step explanation:

a) 2\sqrt{2}=( \sqrt{2}  )^2.\sqrt{2}=(\sqrt{2})^3 = \sqrt{2^3} =\sqrt{8}

b)-7\sqrt{3} =-(\sqrt{7} )^2\sqrt{3} =-\sqrt{7^2.3} =-\sqrt{147}

c)\frac{1}{3} \sqrt{18b} =\frac{1}{3} \sqrt{9.2.b} =\frac{1}{3} \sqrt{3^2.2.b} =\frac{1}{3} \times 3\sqrt{2.b} =\sqrt{2.b}

d)5\sqrt{y} =\sqrt{5^2} \sqrt{y}=\sqrt{25y}

e)-6\sqrt{2a} =-\sqrt{6^2}\sqrt{2a}  = -\sqrt{36.2a} =-\sqrt{72a}

f)-0.1\sqrt{200c}=-\frac{1}{10}  \sqrt{10^2.2c} =-\frac{1}{10}\times10  \sqrt{2c}=-  \sqrt{2c

4 0
3 years ago
Use the given frequency distribution to find the class width, class midpoint, and class boundaries​
Harman [31]

Based on the table attached, the class boundaries are as follows: 43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5.

<h3 /><h3>What is the frequency distribution about?</h3>

Temperature (°F) Frequency

40-44 1

45-49 3

50-54 5

55-59 11

60-64 7

65-69 7

70-74 1

A. Viewing at the frequency table, we find that the lower class limits of two consecutive classes are 40 and 44, respectively. Thus the class width is:

 Class width = 44 − 40= 4

B: One can find the class midpoints by putting the average of the lower and upper class limits. So the midpoint of the first class is  seen below:

=  40  - 44 = \frac{40 + 44}{2}   = 42. In a similar way, we find the rest.

C. The Class boundaries is known to be that which separate the classes removing the class limits. The class boundaries are as follows:

43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5

Therefore, Based on the table attached, the class boundaries are as follows: 43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5.

Learn more about frequency distribution from

brainly.com/question/1094036

#SPJ1

5 0
2 years ago
What is 2x^2 divided by 2
VikaD [51]

Answer:

x^2 or x²

Step-by-step explanation:

2x^2 divided by 2 is

=2x² / 2

=x²

5 0
3 years ago
Read 2 more answers
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