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1 year ago

Use a calculator to find a decimal approximation for the following trigonometric function sin 28°48

Mathematics

1 answer:

Bumek [7]1 year ago

5 0

The decimal approximation for the trigonometric function sin 28°48' is

Given the trigonometric function is sin 28°48'

The ratio between the adjacent side and the hypotenuse is called cos(θ), whereas the ratio between the opposite side and the hypotenuse is called sin(θ). The sin(θ) and cos(θ) values for a given triangle are constant regardless of the triangle's size.

To solve this, we are going to convert 28°48' into degrees first, using the conversion factor 1' = 1/60°

sin (28°48') = sin(28° ₊ (48 × 1/60)°)

= sin(28° ₊ (48 /60)°)

= sin(28° ₊ 4°/5)

= sin(28° ₊ 0.8°)

= sin(28.8°)

= 0.481753

Therefore sin (28°48') is 0.481753.

Learn more about Trigonometric functions here:

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(with steps please) Find the inverse Laplace transform, f(t), of the function: 16/(s-4)^3

Stells [14]

Answer: The required inverse transform of the given function is

$f(t)=8t^2e^{4t}.$

Step-by-step explanation: We are given to find the inverse Laplace transform, f(t), of the following function :

$F(s)=\dfrac{16}{(s-4)^3}.$

We have the following Laplace formula :

$L\{t^ne^{at}\}=\dfrac{n!}{(s-a)^{n+1}}\\\\\\\Rightarrow L^{-1}\{\dfrac{1}{(s-a)^{n+1}}\}=\dfrac{t^ne^{at}}{n!}.$

Therefore, we get

$f(t)\\\\=L^{-1}\{\dfrac{16}{(s-4)^3}\}\\\\\\=16\times\dfrac{t^{3-1e^{4t}}}{(3-1)!}\\\\\\=\dfrac{16}{2}t^2e^{4t}\\\\\\=8t^2e^{4t}.$

Thus, the required inverse transform of the given function is

$f(t)=8t^2e^{4t}.$

6 0

3 years ago

4x + 11y = -3 and -6x = 18y - 6 (substitution method)

dolphi86 [110]

Answer:

-3 + -6= -9

because there is answer given

6 0

3 years ago

Of 560 marbles in a bag, 65% are red and the rest are blue. After 28 red marbles are replaced with blue ones, how many blue marb

jonny [76]

Answer: The answer is 400 blue marbles.

Step-by-step explanation: Given that there are 560 marbles in a bag, out of which 65% are red and rest are blue.

So, number of red marbles is

$n_r=65\%\times 560=\dfrac{65}{100}\times 560=364,$

and number of blue marbles is

$n_b=560-364=196.$

Now, if 28 red marbles are replaced by blue marbles, the the new number of red and blue marbles will be

$n_r^\prime=364-28=336~~~\textup{and}~~~n_b^\prime=196+28=224.$

Now, to get 65% of the marbles blue, we need to add some more blue marbles to the bag. Let 'x' number of blue marbles are added to the bag, then

$65\%\times (560+x)=224+x\\\\\Rightarrow \dfrac{65}{100}\times (560+x)=224+x\\\\\Rightarrow 13(560+x)=20(224+x)\\\\\Rightarrow 7280+13x=4480+20x\\\\\Rightarrow 7x=2800\\\\\Rightarrow x=400.$

Thus, 400 blue marbles need to be added to the bag.

5 0

3 years ago

Read 2 more answers

Please help me out with this question thank you ❤️

devlian [24]

Answer:

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→

Step-by-step explanation:

7 0

3 years ago

Can anyone help me ?

gtnhenbr [62]

The formula for the volume of a sphere is V=(4/3) (pi) r^3. if r is doubled then you get 2r as the radius and V=(4/3) (pi) * 8r^3 so the volume is eight times bigger than the original r value. if r is tripled the r =3r and (3r)^3 so the volume is 27 times bigger. If r is multiplied by n the radius is nr and (nr)^3 =n^3 r^3, Therefore, the volume is n^3 times bigger than the original.

7 0

3 years ago