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Eddi Din [679]
3 years ago
5

Pls help me!! Which two equations are equivalent? y= 1/2x+3 y=x+6 2y=x+6

Mathematics
2 answers:
tia_tia [17]3 years ago
5 0

Answer:

the first and last equation

Step-by-step explanation:

Zigmanuir [339]3 years ago
4 0

Answer:

first and third

Step-by-step explanation:

Consider

y = \frac{1}{2} x + 3 ( multiply through by 2 )

2y = x + 6 ← third equation

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The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM. If 188 sixth graders
Anna007 [38]

Answer:

0.1836 = 18.36% probability that the sample mean would differ from the population mean by greater than 1.46 WPM

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM.

This means that \mu = 84, \sigma = 15

Sample of 188

This means that n = 188, s = \frac{15}{\sqrt{188}}

What is the probability that the sample mean would differ from the population mean by greater than 1.46 WPM?

Greater than 84 + 1.46 = 85.46 or less than 84 - 1.46 = 82.54. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Probability is is less than 82.54.

P-value of Z when X = 82.54. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{82.54 - 84}{\frac{15}{\sqrt{188}}}

Z = -1.33

Z = -1.33 has a p-value of 0.0918

2*0.0918 = 0.1836

0.1836 = 18.36% probability that the sample mean would differ from the population mean by greater than 1.46 WPM

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3 years ago
Please help me solve this problem
Contact [7]
The surface area is 37.5
5 0
4 years ago
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Please answer the question
raketka [301]
Interest is $1,320.  <span><span>P is the principal amount, $6,600.
</span><span>r is the interest rate, 4% per year, or in decimal form, 4/100=0.04.
</span><span>t is the time involved, 5 years time periods.
</span><span>So, t is 5 year time periods.

</span></span>I= p x r x t

In order to get the final number just add $1,320 + $6,600 which is $7,920
7 0
3 years ago
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