Here, first we need to calculate the slope of the line,
m = y2 - y1 / x2-x1
m = 6 + 2 / 3 -1
m = 8/ 2
m = 4
Now, Take first coordinate: y - 6 = 4 (x - 3)
Second coordinate: y + 2 = 4 (x - 1)
In short, Your Answers would be Option A & F
Hope this helps!
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
Answer:
d
Step-by-step explanation:
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