X + 1 + X + 1 + X +1+ X +1 = 2X -3+ 2X -3+ X -1+ X -1
4x + 4 = 4x-6+2x-2
4x+4=6x-8
12=2x
6=x
Side lengths:
6-1=5
6+1=7
2(6)-3=9
Hope that helps! Stay safe!
12 because if you take 2 and add it to 10 you get 12
<em><u>your </u></em><em><u>question:</u></em><em><u> </u></em>
solve 3√125=? by following steps above
<em><u>answer:</u></em>
<em>I'm</em><em> </em><em>not </em><em>sure </em><em>what</em> <em>the </em><em>steps</em><em>"</em><em> </em><em>are </em><em>but </em><em>I </em><em>got </em><em>33.54101966249 </em>
2) longest line is (-1, -3) and (-1, 7)
3) (-1, -3), (-6,2), and (2,4)
An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.
1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46
So we have two possibilities: either #2 or #4. Find least possible pair of integers.
x= first integer
x+1= second integer
x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5
Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.
Hope this helps! :)
