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marissa [1.9K]
3 years ago
13

Given the following  information, find the PERIMETER of the right triangle.

Mathematics
2 answers:
Sergio039 [100]3 years ago
5 0

Answer:

b= 9

Step-by-step explanation:

a^2+b^2=c^2

144+b^2=225

b^2=81

b=9

klasskru [66]3 years ago
3 0
Use Pythagorean theorem
A^2 + B^2 = C^2
12^2 + B^2 = 15^2
Solves for b
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Marsha deposited ​$5,000 into a savings account 2 years ago. The simple interest rate is 3​%. How much money did Marsha earn in​
NARA [144]

Answer:

$300

Step-by-step explanation:

(5000)(2)(3/100)

=300

7 0
3 years ago
Leslie decides to join a gym. She must pay a monthly fee plus a one-time fee to open a membership. This situation can be modeled
liq [111]

Answer:

see below (I hope this helps!)

Step-by-step explanation:

The x seems to represent the number of months that Leslie has joined the gym for. When x = 0 (basically when she hasn't started using her membership), she pays 55(0) + 50 = $50 so we know that the 50 represents the one-time fee. The only thing missing is the monthly fee and since we haven't defined what the 55 means, we can conclude that the 55 represents the monthly fee. This makes sense because 55x is simply 55 times x, and since x is the number of months, 55 times that would be how much Leslie pays per month, otherwise known as the monthly fee.

8 0
3 years ago
5 + 3x - 2 for in the simplest form
emmasim [6.3K]

Answer:

3x +3

Step-by-step explanation:

5 + 3x - 2

Combine like terms

3x  +5-2

3x +3

8 0
3 years ago
Read 2 more answers
-6+3y=12 solve for x
Roman55 [17]

Answer:

The answer is y=6

Step-by-step explanation:

Move the constant to the right side and change its sign

3y=12+6

Add the numbers

12 +6

3y=18

Divide both sides of the equation by 3

Which equals

Y=6

Hope that helps

5 0
4 years ago
The population of a town is 6500 and is increasing at a rate of 4% each year. Create a function for this scenario. At this rate,
Stella [2.4K]

Answer:

P_4 = 7604.08

Step-by-step explanation:

If the population increases at a rate of 4% per annum, then:

In year 1:

P_1 = P_0 + 0.04P_0

Where P_0 is the initial population and P_n is the population in year n

In year 2

P_2 = P_1 + 0.04P_1

It can also be written as:

P_2 = P_0 + 0.04P_0 + 0.04 (P_0 + 0.04P_0)

Taking out common factor P_0

P_2 = (1 + 0.04) (P_0) + 0.04P_0 (1 + 0.04)

Taking out common factor (1 + 0.04)

P_2 = (1 + 0.04) (P_0 + 0.04P_0)

Taking out again common factor P_0

P_2 = (1 + 0.04) (1 + 0.04) P_0

Simplifying

P_2 = P_0 (1 + 0.04) ^ 2


So

P_n = P_0 (1 + 0.04) ^ n

This is the equation that represents the population for year n

Then, in 4 years, the population will be:

P_4 = P_0 (1 + 0.04) ^ 4\\P_4 = 6500(1 + 0.04) ^ 4\\P_4 = 7604.08

3 0
3 years ago
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