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1 year ago

In lines 24-27 ("Let . . . pastime"), the country

1 answer:

7 0

In lines 24-27 ("Let . . . pastime"), the country described is noteworthy because children and parents share many activities.

<h3>What is the meaning of noteworthy?</h3>

A notable contribution is one that is deserving of praise or attention in particular because of some exceptional excellence. Additional Words from Notable. Our personnel adheres to the Code of Practice, and Noteworthy supports the work of the Press Council of Ireland and the Office of the Press Ombudsman. Noteworthy banknotes look and feel like top-of-the-line cash while offering the highest grade of digital security directly built in each note. They are equipped with a secure cryptographic microprocessor and the best security features available in the banknote industry. The proprietary score-writing program Noteworthy Composer was created by Noteworthy Software.

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Find the base of an isosceles triangle whose area is 60 cm² and the length of one of its equal sides is 13 cm.

Kobotan [32]

Answer:

Base = 24 cm or 10cm

Step-by-step explanation:

REMEMBER:
An isosceles triangle ABC with base BC = ‘b' & height AD = ‘h' & its equal sides =13 cm & area = 60 cm²

Using the formulas

$A=\frac{bh_b}{2}$

$h_b=\sqrt{a^2-\frac{b^2}{4} }$

There are 2 solutions for $b$

$b=2\sqrt{2} \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2+\sqrt{13^4-4*60^2} } }$ ≈ $10cm$ $b=2\sqrt{2} \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2-\sqrt{13^4-4*60^2} } }=24cm$

Less complex:

Area of a triangle = 1/2 * b * h = 60

=> h = 120/b

In right triangle ABD

13² = h² + b² /4 ( by Pythagoras law)

=>169 = 120²/b² + b²/4

=>676 b² = 57600 + b^4

=> b^4 - 676 b² + 57600 = 0

=> b² = 676 +- √(676² - 4*57600) / 2

=> b²= 676 +- √(226576) /2

=> b² = (676 +- 476 )/2

=> b² = 1152/2 , 200 /2

=> b² = 576 , 100

=> b = 24, 10

So, Base = 24 cm or 10cm

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