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Step2247 [10]
3 years ago
8

How do you find the length of a line in a circle?​

Mathematics
1 answer:
GREYUIT [131]3 years ago
8 0

Answer:

How to calculate and derive the formula for the Chord Length of a circle. The formula for the chord length is: 2rsin(theta/2) where r is the radius of the circle and theta is the angle from the centre of the circle to the two points of the chord.

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Please help me with this question I will give brainliest.
Ainat [17]

Answer:

All you need to remember is the rules

Step-by-step explanation:

Let us remember

a to the m power x a to the nth power is = a to the m+n power. (add the exponents)

And

a to the m power ÷ a to the nth power is = a to the m-n power. (subtract the exponents) So

14 to the -4 power x 14 to the 7 power= 14 to the -4+7 which is equal to 14 to the 3rd power

6 0
3 years ago
What is the perimeter of a rhombus whose diagonals measure 42cm and 56cm?
Trava [24]

Answer:

676

Step-by-step explanation:

d1×d2/2

42×56/2

1352/2=676

please check it by doing again

3 0
3 years ago
Read 2 more answers
Mr. Weiss is ordering parts for his wheelchair on the Internet. The website is offering 15% off orders over $250.
aleksandrvk [35]

Answer:

$230.65

Step-by-step explanation:

$179 marked down by 35 % = $116.35

computer mount= $99

cell holder= $56

total= $271.35

marked down by 15% = $230.65 (230.6475)

6 0
3 years ago
Express the number 180 as the sum of four numbers that form a geometric
ale4655 [162]

Answer:

dadadddddddddddddddddddd

Step-by-step explanation:

ddasddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd

6 0
2 years ago
Write the equation of the line that is perpendicular to 3x+2y=8 and goes through the point (-5,2)
kifflom [539]

Answer:

\displaystyle y=\frac{2}{3}(x+5)+2

Step-by-step explanation:

We need to find the equation of the line perpendicular to the line 3x+2y=8 and passes through (-5,2).

The given line can be expressed as:

\displaystyle y=-\frac{3}{2}x+4

We can see the slope of this line is m1=-3/2.

The slopes of two perpendicular lines, say m1 and m2, meet the condition:

m_1.m_2=-1

Solving for m2:

\displaystyle m_2=-\frac{1}{m_1}

\displaystyle m_2=-\frac{1}{-\frac{3}{2}}

\displaystyle m_2=\frac{2}{3}

Now we know the slope of the new line, we use the slope-point form of the line:

y=m(x-h)+k

Where m is the slope and (h,k) is the point. Using the provided point (-5,2):

\boxed{\displaystyle y=\frac{2}{3}(x+5)+2}

6 0
3 years ago
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