hey mate,
![x^2 + 8x + 16 = 0](https://tex.z-dn.net/?f=x%5E2%20%2B%208x%20%2B%2016%20%3D%200)
<=>
![(x+4)^2 = 0](https://tex.z-dn.net/?f=%28x%2B4%29%5E2%20%3D%200)
As we know that ![(a+b)^2 = a^2+b^2+2ab](https://tex.z-dn.net/?f=%28a%2Bb%29%5E2%20%3D%20a%5E2%2Bb%5E2%2B2ab)
then
![(x+4)^2 = 0](https://tex.z-dn.net/?f=%28x%2B4%29%5E2%20%3D%200)
<=> (x+4) = 0
<=> x = -4
so there is one solution x = -4
thanks
-7,1,3
Domain is the x
Range is the y
Step-by-step explanation:
Let us take ratio constant as 'x'
Therefore ratio of angles
3x:5x:9x:13x
Sum of interior angles of quadrilateral is 360 degree.
3x+5x+9x+13x=sum of interior angles of quadrilateral
=>3x+5x+9x+13x=360
=>30x=360
=>x=12
To solve this you have to use inverse operations, which means divide 14 from both sides.
x= 1.5
Answer:
Option b.
Step-by-step explanation:
we have
![2(\frac{3}{5})^{3}](https://tex.z-dn.net/?f=2%28%5Cfrac%7B3%7D%7B5%7D%29%5E%7B3%7D)
Evaluate
![2(\frac{3}{5})^{3}=2(\frac{3^{3}}{5^{3}})\\ \\=2(\frac{27}{125})\\ \\=\frac{54}{125}](https://tex.z-dn.net/?f=2%28%5Cfrac%7B3%7D%7B5%7D%29%5E%7B3%7D%3D2%28%5Cfrac%7B3%5E%7B3%7D%7D%7B5%5E%7B3%7D%7D%29%5C%5C%20%5C%5C%3D2%28%5Cfrac%7B27%7D%7B125%7D%29%5C%5C%20%5C%5C%3D%5Cfrac%7B54%7D%7B125%7D)
therefore
He did not apply the power to the denominator of 3/5