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3 years ago

Simplify the following proper fraction by reducing to lowest terms. 2/18

Mathematics

2 answers:

Damm [24]3 years ago

4 0

Answer:1/9

Step-by-step explanation: divide both sides of the fraction by 2

Gnoma [55]3 years ago

3 0

Answer:

1/9

both divide by 2 then 2/2=1 and 18/2=9 so that the answer will be 1/9

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How is 0.55 you're answer for 4.4 divided by 8?

uranmaximum [27]

So, what I usually do is draw a division box, put the numerator (4.4) in and the denominator out and then do a normal division.

5 0

4 years ago

HELLP PLSS (-2 and 1/9) - (-4 and 1/3) = x Find the value of x

dedylja [7]

Answer:

x = 20/9

Step-by-step explanation:

We want to write out all of the mixed fractions into improper fraction form. So -2 and 1/9 becomes -19/9 and -4 and 1/3 becomes -13/3. Then we get (-19/9) - (-13/3). The two minus signs together means a positive/plus sign, so we get -19/9 + 13/3. In order to add, we want the denominator to be the same. A common denominator could be 9, so -19/9 + 13(3)/3(3) = -19/9 + 39/9 = 20/9, which is our final answer

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2 years ago

A 2-liter bottle of juice costs $2.80. A box containing six 12-liter bottles sells for $3.90. Which option has a higher cost per

barxatty [35]

Answer:The first option has a higher cost per liter and the required cost is $1.40 per liter.

Step-by-step explanation:

Step-by-step explanation: Given that a 2 liter bottle of juice cost $2.80. A box containing six 12 liter bottle sells for $3.90.

We are to select the option that has a higher cost per liter.

We will be using the UNITARY method to solve the given problem.

Option (1) :

The cost of 2 liter bottle of juice = $2.80.

So, the cost of 1 liter bottle of juice will be

Option (2) :

The cost of six 12 liters bottle of juice = $3.90.

So, the cost of 1 liter bottle of juice will be

Since 0.05>1.40, so the option of 2 liter bottle costing $2.80 has a higher cost per liter.

And, the required cost is $1.40 per liter.

7 0

3 years ago

What to numbers can go into 72 and 45

ratelena [41]

Answer:

3 and 9

Step-by-step explanation:

3 * 24 = 72

9 * 8 = 72

3 * 15 = 45

9 * 5 = 45

8 0

3 years ago

Read 2 more answers

a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was

Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

Let $\bar X$ = sample average time spent studying

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean hours spent studying = 25 hours

$\sigma$ = standard deviation = 15 hours

n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < $\bar X$ < 30 hours)

P(29 hours < $\bar X$ < 30 hours) = P( $\bar X$ < 30 hours) - P( $\bar X$ $\leq$ 29 hours)

P( $\bar X$ < 30 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 30-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z < 2) = 0.97725

P( $\bar X$ $\leq$ 29 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 29-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z $\leq$ 1.60) = 0.94520

So, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.

Therefore, P(29 hours < $\bar X$ < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0

3 years ago