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KatRina [158]
2 years ago
10

In c++ a repetition statement continues looping until the relational expression in the statement evaluates to ____.

Computers and Technology
1 answer:
tatiyna2 years ago
8 0

Answer: False

Explanation: In c++ a repetition statement continues looping until the relational expression in the statement evaluates to false.

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A bubble starts by comparing the first item in the list to all the remaining items, and swaps where the first item is ____ a lat
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In cell M2, enter a formula using a nested IF function as follows to determine first if a student has already been elected to of
aleksley [76]

Answer:

Following are the code to this question:

code:

=IF(EXACT(I2,"Yes"),"Elected",IF(EXACT(K2,"Yes"),"Yes","No"))

Explanation:

In the given the data is not defined so we explain only  the above code, but before that, we briefly define working of if the function that can be defined as follows:

  • The If() function, is used only when one of the logical functions and its value must return the value true. or we can say it only return a true value.
  • In the above function, a column "Elected" is used that uses other column values to check this column value is equal if this condition is true it will return "yes" value.

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3 years ago
Describe the Order of Operations in Java programming.
cestrela7 [59]

Answer:

It stands for Parentheses, Exponents, Multiplication/Division, Addition/Subtraction. PEMDAS is often expanded to the mnemonic "Please Excuse My Dear Aunt Sally" in schools. Canada and New Zealand use BEDMAS, standing for Brackets, Exponents, Division/Multiplication, Addition/Subtraction.

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3 years ago
A blood bank maintains two tables - DONOR, with information about people who are willing to donate blood and ACCEPTOR, with info
Kipish [7]

Answer:

The sql query is given below.

Since we need to count of males and females for a particular blood group, we put xxx for the blood group.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors,

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

Explanation:

The clauses in the query are as follows.

1. SELECT: all the columns required in the output are put in this clause.

2. FROM JOIN ON: the table(s) from which the above columns are taken are put in this clause.

3. WHERE: any condition required to filter the output is put in this clause.

The query is explained below.

1. Find the number of male donors. Number of anything can be found using COUNT() function. A query is required since gender is included in deciding the type of donor.

2. The query is defined to find number of male donors as follows.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "M%"; )

3. In the previous query, LIKE operator is used since it is not defined what value is stored for male donors.

4. Similarly, the query to find the number of female donors is formed.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "F%"; )

5. Next, the final query is formed as follows.

SELECT: both COUNT() functions will come here.

FROM: table name

WHERE: specific blood group will be put here

GROUP BY: this clause is optional and is not used in this query.

HAVING: this clause is optional and is not used in this query.

6. The query after putting all clauses is shown below.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%"),

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%")

FROM DONOR

WHERE BG = xxx;

7. Alias is used in the above query for each column to get the final query.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors, COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

7 0
3 years ago
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