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2 years ago

Hey guys! Can anyone help me out with this question?? I'm really confused. Thanks!

Mathematics

1 answer:

lions [1.4K]2 years ago

7 0

Answer:

No, yes, no, yes

Step-by-step explanation:

Lines are only perpendicular if their gradients multiply to -1.

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Find the geometric mean of 25 and 100.<br> A. 50<br> B. 62.5<br> C. 1250<br> D. 2500

Debora [2.8K]

<h3>Answer: Choice A) 50</h3>

For two numbers x and y, the geometric mean is G = sqrt(x*y)

In this case, x = 25 and y = 100, so

G = sqrt(x*y)

G = sqrt(25*100)

G = sqrt(2500)

G = 50

8 0

3 years ago

Jenny used the expression -16x2 + 38x + 5 to determine the height of an object x seconds after it was hit into the air. Write an

Masteriza [31]

Answer:

0 < x < 2.5

Step-by-step explanation:

-16x² + 38x + 5 = 0

-16x² + 40x - 2x + 5 = 0

-8x(2x-5) - 1(2x-5) = 0

x = -⅛ , 2.5

0 < x < 2.5

7 0

4 years ago

Simplify -|-7 + 4| Quick please

max2010maxim [7]

Answer:- | -7 + 4 |

= - | -3 | Since | -3 | = 3:

= - (3)

= - 3

8 0

3 years ago

Read 2 more answers

A tobacco company claims that the nicotine content of its "light" cigarettes has a mean of milligrams and a standard deviation o

valina [46]

The missing values in the given question is shown below.

A tobacco company claims that the nicotine content of its "light" cigarettes has a mean of 1.5 milligrams and a standard deviation of 0.52 milligrams. What is the probability that 50 randomly selected light cigarettes from this company will have a total combined nicotine content of 81 milligrams or less, assuming the company's claims to be true? Carry your intermediate computations to at least four decimal places. Report your result to at least three decimal places.

Answer:

P(x ≤ 1.62) = 0.949 to three decimal places.

Step-by-step explanation:

From the question; given that:

The population mean = 1.5

The standard deviation = 0.52

The sample size n = 50

The sample mean $\overline x = \dfrac{81}{50}$ = 1.62

Hence; we can calculate the required probability as:

$P( x \leq 1.62) = P \bigg (\dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{\overline x -1.5 }{\dfrac{\sigma}{\sqrt{n}}} \bigg )$

$P( x \leq 1.62) = P \bigg (Z \leq \dfrac{1.62 -1.5 }{\dfrac{0.52}{\sqrt{50}}} \bigg )$

$P( x \leq 1.62) = P \bigg (Z \leq \dfrac{0.12 }{\dfrac{0.52}{\sqrt{50}}} \bigg )$

$P( x \leq 1.62) = P \bigg (Z \leq 1.632 \bigg )$

From z - tables;

P(x ≤ 1.62) = 0.9486

P(x ≤ 1.62) = 0.949 to three decimal places.

7 0

3 years ago

3a-b=-9 -3a-2b=0 solve by elimination

anzhelika [568]

a = –2 and b = 3

Solution:

Given equations are

3a – b = –9 – – – – (1)

–3a – 2b = 0 – – – – (2)

To solve these equations by elimination method.

Elimination method means eliminating one variable to find the other variable.

Add equation (1) with equation (2), we get

3a – b + (–3a – 2b) = –9 + 0

⇒ 3a – b – 3a – 2b = –9

Combine like terms together.

⇒ 3a – 3a – b – 2b = –9

⇒ 0 – 3b = –9

⇒ – 3b = –9

Divide by (–3) on both sides, we get

⇒ b = 3

Substitute b = 3 in equation (1), we get

(1) ⇒ 3a – b = –9

⇒ 3a – 3 = –9

Add 3 on both sides of the equation,

⇒ 3a = –6

Divide 3 on both sides of the equation

⇒ a = –2

Hence, a = –2 and b = 3.

8 0

4 years ago